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Sixty four spherical drops each of radius 2cm and carrying 5c charge combine to form a bigger drop ,its capacity is?
Most Upvoted Answer
Sixty four spherical drops each of radius 2cm and carrying 5c charge c...
Calculation of Capacity of Bigger Drop


Step 1: Calculation of Total Charge



  • Each spherical drop has radius = 2cm and charge = 5c

  • Volume of each drop = (4/3)πr³ = (4/3)π(2cm)³ = 32/3 π cm³

  • Total volume of 64 drops = 64 × (32/3) π cm³ = 682.67 π cm³

  • Total charge of 64 drops = 64 × 5c = 320c



Step 2: Calculation of Radius of Bigger Drop



  • Let the radius of bigger drop be R

  • Volume of bigger drop = (4/3)πR³

  • Equating the volumes of 64 drops and bigger drop: (4/3)πR³ = 682.67 π cm³

  • Solving for R, we get R = 8 cm



Step 3: Calculation of Capacity of Bigger Drop



  • Capacity of a conductor is given by the formula: C = Q/V

  • Where Q is charge and V is potential

  • For a spherical conductor, capacity is given by the formula: C = 4πεR

  • Where ε is the permittivity of free space and R is the radius of the conductor

  • Substituting the values, we get C = 4 × π × 8 × ε = 32 π ε

  • Using the value of permittivity of free space, ε = 8.85 × 10⁻¹² F/m

  • Therefore, capacity of the bigger drop = 32 π × 8.85 × 10⁻¹² F/m = 8.84 × 10⁻¹⁰ F



Final Answer


Capacity of the bigger drop is 8.84 × 10⁻¹⁰ F.
Community Answer
Sixty four spherical drops each of radius 2cm and carrying 5c charge c...
The charge of the bigger drop will be
Q= 5 * 64= 320C
The radius of bigger drop
64^1/3 × 2cm= 8cm
The potential of bigger drop
KQ/R= 9×10^9 ×320/8×10^-2(for cm to m)
= 36×10^12
Capacity= Q/V
= 320/ 36×10^12
= 80/9 ×10^-12
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Sixty four spherical drops each of radius 2cm and carrying 5c charge combine to form a bigger drop ,its capacity is?
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