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eight small drops each of radius r and having same charge q are combined to form big drop .the ratio betn the potential of the bigger drop and smaller drop is
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eight small drops each of radius r and having same charge q are combin...
Introduction
When small charged droplets combine to form a larger droplet, the potential of the new droplet can be determined based on the principles of electrostatics.
Charge Distribution
- Each small drop has a charge 'q'.
- When eight small drops combine, the total charge 'Q' of the big drop becomes:
- Q = 8q
Volume and Radius Relationship
- The volume of a spherical droplet is given by:
- V = (4/3)πr³
- The volume of the big drop (V_big) is:
- V_big = 8 * V_small = 8 * (4/3)πr³
- Thus, the radius of the big drop (R) can be derived from its volume:
- R³ = 8 * r³
- R = 2r
Potential of the Droplets
- The electric potential (V) of a charged sphere is given by:
- V = k * Q / R, where k is Coulomb's constant.
- For the small drop:
- V_small = k * q / r
- For the big drop:
- V_big = k * Q / R = k * (8q) / (2r) = (4k * q) / r
Ratio of Potentials
- The ratio of the potential of the big drop to that of the small drop can be calculated:
- Ratio = V_big / V_small = [(4k * q) / r] / [k * q / r] = 4
Conclusion
The ratio between the potential of the bigger drop and that of the smaller drop is 4. This illustrates how combining charged droplets alters their electrostatic potential due to changes in size and charge distribution.
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eight small drops each of radius r and having same charge q are combined to form big drop .the ratio betn the potential of the bigger drop and smaller drop is
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