If the average daily water consumption of a city is 24000 cum, the peak hourly demand (of the maximum day) will be
  • a)
    1000 cum/hr
  • b)
    1500 cum/hr
  • c)
    1800 cum/hr
  • d)
    2700 cum/hr
Correct answer is option 'D'. Can you explain this answer?

Civil Engineering (CE) Question

Vivek Pandit
Jun 30, 2018
Q= 24000cum MHD= 2.7q= 2.7*24000/24=2700 cum/hr

Akash Singh
Nov 05, 2018
Avg. water consumption per hour = 24000/24 = 1000 cum/hr
then,peak hourly demand =2.7×Avg. water consumption = 2.7 × 1000 = 2700 cum/hr

Pankaj Sharma
Nov 06, 2018
Q = 24000 Max. Hourly water demand = 2.7 * Q = 2.7 * 24000 = 64800 cum / Day = 64800 / 24 = 2700 cum/hr

Nabina Shyam
Nov 09, 2018
PHD=2.7XAVG. DAILY WATER CONSUMPTION/24 =2.7X24000/24 =2700 cum/hr

Mohit Malik
Nov 09, 2018
Why multiplying by 2.7

Vikash Rawani
Feb 18, 2019
Pick hourly demand is tkaen as 2.7 times of average hourly demand.

Hemanth Roy
May 29, 2019
Actual formula is 2.7q.
q=24000/24 = 1000
2.7q=2.7*1000 = 2700

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