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# If the average daily water consumption of a city is 24000 cum, the peak hourly demand (of the maximum day) will bea)1000 cum/hrb)1500 cum/hrc)1800 cum/hrd)2700 cum/hrCorrect answer is option 'D'. Can you explain this answer? Related Test: Test: Environment Engineering Practices- 1

## Civil Engineering (CE) Question

 Vivek Pandit Jun 30, 2018
Q= 24000cum MHD= 2.7q= 2.7*24000/24=2700 cum/hr

 Drishti Verma Sep 26, 2018

 Akash Singh Nov 05, 2018
Avg. water consumption per hour = 24000/24 = 1000 cum/hr
then,peak hourly demand =2.7×Avg. water consumption = 2.7 × 1000 = 2700 cum/hr

 Pushkar Malik Nov 06, 2018

 Pankaj Sharma Nov 06, 2018
Q = 24000 Max. Hourly water demand = 2.7 * Q = 2.7 * 24000 = 64800 cum / Day = 64800 / 24 = 2700 cum/hr

 Nabina Shyam Nov 09, 2018
PHD=2.7XAVG. DAILY WATER CONSUMPTION/24 =2.7X24000/24 =2700 cum/hr

 Mohit Malik Nov 09, 2018
Why multiplying by 2.7

 Vikash Rawani Feb 18, 2019
Pick hourly demand is tkaen as 2.7 times of average hourly demand.

 Hemanth Roy May 29, 2019
Actual formula is 2.7q.
q=24000/24 = 1000
2.7q=2.7*1000 = 2700

 Manish Kumar Jan 30, 2019
1800cum/hr

 Chess Lovers Jul 12, 2019
2700