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If @ # $ % & is decoded as ARGUE and α β γ δ & is SOLVE, what is δ @ $% &γ ∠ ?

  • a)
    VAGUELY

  • b)
    VAGRANT

  • c)
    VAGUELE

  • d)
    VAGUER

Correct answer is option 'A'. Can you explain this answer?
?
Most Upvoted Answer
If@ # $ % &is decoded asARGUEandα β γ δ &am...
Understanding the Code
To decode the given strings, we need to analyze the mappings:
- If "@ # $ % &" is decoded as "ARGUE"
- And "α β γ δ &" is decoded as "SOLVE"
Let's break down the mappings based on letter positions.
Mapping Analysis
- Each symbol corresponds to a specific letter in the English alphabet:
- @ = A
- # = R
- $ = G
- % = U
- & = E (the last character in "ARGUE")
- For "SOLVE":
- α = S
- β = O
- γ = L
- δ = V
- & = E (the last character in "SOLVE")
Decoding the Target Code
Now, let's decode the expression "δ @ $% & γ ∠":
- δ = V
- @ = A
- $ = G
- % = U
- & = E
- γ = L
Combining these decoded letters gives us:
- V A G U E L
However, we have an extra symbol "∠".
Identifying the Extra Symbol
In this context, "∠" does not correspond to any specific letter that we have seen so far. Given the options provided, we need to select a word that closely matches our decoded letters:
- a) VAGUELY
- b) VAGRANT
- c) VAGUELE
- d) VAGUER
The best match derived from the letters we decoded (VAGUE) is option 'A' - VAGUELY.
Conclusion
The correct answer is option 'A' (VAGUELY) since it is the only option that can be formed from the initial decoded letters while maintaining a logical connection.
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