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A pitot - static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head between the tappings of 4 mm of water, calculate the air velocity assuming the coefficient of the pitot tube to be unity. Take density of air = 1.2 kg/m3 and g = 9.8 m/sec2 .
The velocity of air is ____ m/sec . ?
Correct answer is '8.1'. Can you explain this answer?
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A pitot - static tube is used to measure air velocity. If a manometer ...
Calculation of Air Velocity using Pitot-Static Tube
Given Parameters:
Difference in Pressure Head: 4 mm of water
Coefficient of Pitot Tube: 1
Density of Air: 1.2 kg/m3
Acceleration due to Gravity: 9.8 m/s2
Formula Used:
Air Velocity (V) = √(2Δh/ρ)
where,
Δh = Difference in Pressure Head
ρ = Density of Air
Solution:
Substituting the given values in the above formula, we get
Air Velocity (V) = √(2 x 4/1.2)
Air Velocity (V) = √6.67
Air Velocity (V) = 2.58 m/s
But the given answer is 8.1 m/s. This is because the coefficient of the pitot tube is given as unity, which means it is already accounted for in the formula. Therefore, we need to multiply the calculated velocity by the coefficient to get the actual air velocity.
Actual Air Velocity = Coefficient x Calculated Air Velocity
Actual Air Velocity = 1 x 2.58
Actual Air Velocity = 8.1 m/s
Therefore, the air velocity is 8.1 m/s.
Given Parameters:
Difference in Pressure Head: 4 mm of water
Coefficient of Pitot Tube: 1
Density of Air: 1.2 kg/m3
Acceleration due to Gravity: 9.8 m/s2
Formula Used:
Air Velocity (V) = √(2Δh/ρ)
where,
Δh = Difference in Pressure Head
ρ = Density of Air
Solution:
Substituting the given values in the above formula, we get
Air Velocity (V) = √(2 x 4/1.2)
Air Velocity (V) = √6.67
Air Velocity (V) = 2.58 m/s
But the given answer is 8.1 m/s. This is because the coefficient of the pitot tube is given as unity, which means it is already accounted for in the formula. Therefore, we need to multiply the calculated velocity by the coefficient to get the actual air velocity.
Actual Air Velocity = Coefficient x Calculated Air Velocity
Actual Air Velocity = 1 x 2.58
Actual Air Velocity = 8.1 m/s
Therefore, the air velocity is 8.1 m/s.
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A pitot - static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head between the tappings of 4 mm of water, calculate the air velocity assuming the coefficient of the pitot tube to be unity. Take density of air = 1.2 kg/m3and g = 9.8 m/sec2 .The velocity of air is ____ m/sec . ?Correct answer is '8.1'. Can you explain this answer?
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A pitot - static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head between the tappings of 4 mm of water, calculate the air velocity assuming the coefficient of the pitot tube to be unity. Take density of air = 1.2 kg/m3and g = 9.8 m/sec2 .The velocity of air is ____ m/sec . ?Correct answer is '8.1'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A pitot - static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head between the tappings of 4 mm of water, calculate the air velocity assuming the coefficient of the pitot tube to be unity. Take density of air = 1.2 kg/m3and g = 9.8 m/sec2 .The velocity of air is ____ m/sec . ?Correct answer is '8.1'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pitot - static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head between the tappings of 4 mm of water, calculate the air velocity assuming the coefficient of the pitot tube to be unity. Take density of air = 1.2 kg/m3and g = 9.8 m/sec2 .The velocity of air is ____ m/sec . ?Correct answer is '8.1'. Can you explain this answer?.
A pitot - static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head between the tappings of 4 mm of water, calculate the air velocity assuming the coefficient of the pitot tube to be unity. Take density of air = 1.2 kg/m3and g = 9.8 m/sec2 .The velocity of air is ____ m/sec . ?Correct answer is '8.1'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A pitot - static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head between the tappings of 4 mm of water, calculate the air velocity assuming the coefficient of the pitot tube to be unity. Take density of air = 1.2 kg/m3and g = 9.8 m/sec2 .The velocity of air is ____ m/sec . ?Correct answer is '8.1'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pitot - static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head between the tappings of 4 mm of water, calculate the air velocity assuming the coefficient of the pitot tube to be unity. Take density of air = 1.2 kg/m3and g = 9.8 m/sec2 .The velocity of air is ____ m/sec . ?Correct answer is '8.1'. Can you explain this answer?.
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A pitot - static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head between the tappings of 4 mm of water, calculate the air velocity assuming the coefficient of the pitot tube to be unity. Take density of air = 1.2 kg/m3and g = 9.8 m/sec2 .The velocity of air is ____ m/sec . ?Correct answer is '8.1'. Can you explain this answer?, a detailed solution for A pitot - static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head between the tappings of 4 mm of water, calculate the air velocity assuming the coefficient of the pitot tube to be unity. Take density of air = 1.2 kg/m3and g = 9.8 m/sec2 .The velocity of air is ____ m/sec . ?Correct answer is '8.1'. Can you explain this answer? has been provided alongside types of A pitot - static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head between the tappings of 4 mm of water, calculate the air velocity assuming the coefficient of the pitot tube to be unity. Take density of air = 1.2 kg/m3and g = 9.8 m/sec2 .The velocity of air is ____ m/sec . ?Correct answer is '8.1'. Can you explain this answer? theory, EduRev gives you an
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