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 A stone of mass m tied to a string of length l is rotating along a circular path with constant speed v. The torque on the stone is
  • a)
    zero
  • b)
    mvl
  • c)
    mv/l
  • d)
    mv2/l
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A stone of mass m tied to a string of length l is rotating along a cir...
Hence the torque is zero .Because the line of action of the tension passes through the centre .So lever arm of tension is zero So the torque acting is also zero .

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Community Answer
A stone of mass m tied to a string of length l is rotating along a cir...
**Explanation:**

To understand why the torque on the stone is zero, let's break down the concept step by step.

**1. Torque:**
Torque is defined as the rotational equivalent of force. It describes the tendency of a force to rotate an object about an axis. Mathematically, torque is given by the equation:

Torque (τ) = r * F * sin(θ)

where r is the perpendicular distance from the axis of rotation to the line of action of the force, F is the magnitude of the force, and θ is the angle between the force vector and the line connecting the axis of rotation and the point of application of the force.

**2. Circular Motion:**
In circular motion, an object moves along a circular path with a constant speed. The object experiences a centripetal force directed towards the center of the circle, which provides the necessary inward acceleration to keep the object moving in a circle.

In this scenario, the stone tied to the string is rotating along a circular path. The tension in the string provides the centripetal force required for the circular motion.

**3. Torque on the Stone:**
In the given scenario, the stone is rotating with a constant speed v along a circular path of radius l. The tension in the string exerts a force towards the center of the circle, i.e., along the radial direction.

Since the force is acting along the radial direction, the angle θ between the force vector and the line connecting the axis of rotation and the point of application of the force is zero degrees. Therefore, sin(θ) = 0.

Substituting sin(θ) = 0 into the torque equation, we get:

Torque (τ) = r * F * sin(θ)
= r * F * 0
= 0

Thus, the torque on the stone is zero.

**Conclusion:**
The correct answer is option 'A' (zero). Since the force responsible for the circular motion is acting along the radial direction, the torque on the stone is zero.
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