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 If f(x) = x2 – x + 1; g(x) = 7x – 3, be two real functions then (f + g)(3) is
  • a)
    25
  • b)
    3
  • c)
    7
  • d)
    18
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
If f(x) = x2– x + 1; g(x) = 7x – 3, be two real functions ...
 f(x) = x2 – x + 1; g(x) = 7x – 3
(f+g)(x) = (x2 - x + 1 + 7x - 3)
=(x2 - x + 7x + 1 - 3)
= x2 + 6x - 2
(f+g)(3) = x2 + 6x - 2
= (3)2 + 6(3) - 2
= 9 + 18 - 2
= 25
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Most Upvoted Answer
If f(x) = x2– x + 1; g(x) = 7x – 3, be two real functions ...
Given f(x) = x2 – x + 1 g(x)= 7x – 3 so (f + g)(3)  then put x=3 f(3)+g(3) =x^2 – x + 1+7x – 3 =(3)^2-(3)+1+7(3)-3 =9-3+1+21-3 =6+1+18 =7+18 =25
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If f(x) = x2– x + 1; g(x) = 7x – 3, be two real functions ...
Answer:

Given functions:
f(x) = x^2 + x + 1
g(x) = 7x - 3

To find (f + g)(3), we need to substitute x = 3 into both functions and then add the results.

Step 1: Evaluate f(3)
Substituting x = 3 into f(x), we get:
f(3) = (3)^2 + 3 + 1
= 9 + 3 + 1
= 13

Step 2: Evaluate g(3)
Substituting x = 3 into g(x), we get:
g(3) = 7(3) - 3
= 21 - 3
= 18

Step 3: Find (f + g)(3)
(f + g)(3) = f(3) + g(3)
= 13 + 18
= 31

Therefore, the correct answer is option 'A', which is 31.

Summary:
To find (f + g)(3), we substitute x = 3 into both functions f(x) and g(x), evaluate the results, and then add them together. The final result is 31.
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If f(x) = x2– x + 1; g(x) = 7x – 3, be two real functions then (f + g)(3) isa)25b)3c)7d)18Correct answer is option 'A'. Can you explain this answer?
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