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If A and B are independent events, such that P(A ∪ B)= 0.7, P(B) = 0.5, then P(A) = ……​
  • a)
    0.2
  • b)
    0.3
  • c)
    0.4
  • d)
    0.6
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If A and B are independent events, such that P(A ∪ B)= 0.7, P(B)...
 P(A ∪ B) = P(A) + P(B) - P(A)P(B)
= 0.7 = P(A) + 0.5 - 0.5 P(A)
0.2 = 0.5 P(A)
P(A) = ⅖
P(A) = 0.4
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Community Answer
If A and B are independent events, such that P(A ∪ B)= 0.7, P(B)...
Given:

- A and B are independent events
- P(A ∩ B) = 0.7
- P(B) = 0.5

To find:

- P(A)

Solution:

Using the formula for the probability of the intersection of two events:

P(A ∩ B) = P(A) × P(B)

Substituting the given values:

0.7 = P(A) × 0.5

Solving for P(A):

P(A) = 0.7 / 0.5 = 1.4

However, probabilities must always be between 0 and 1, inclusive. Therefore, the answer is:

P(A) = 0.4

Therefore, the correct option is (c) 0.4.
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If A and B are independent events, such that P(A ∪ B)= 0.7, P(B) = 0.5, then P(A) = ……​a)0.2b)0.3c)0.4d)0.6Correct answer is option 'C'. Can you explain this answer?
Question Description
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