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A solid circular compression member 50mm in diameter is to be replaced by a hollow circular section of the same material. Find the size of hollow section if internal diameter is 0.6 times external diameter.
  • a)
    Douter = 40mm, Dinner = 24mm
  • b)
    Douter = 63.1mm, Dinner = 37.86mm
  • c)
    Douter = 51.7mm, Dinner = 31mm
  • d)
    Douter = 71mm, Dinner = 42.6mm
Correct answer is option 'C'. Can you explain this answer?
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To find the size of the hollow section, we need to compare the cross-sectional areas of the solid and hollow sections.

Let's assume the external diameter of the hollow section is D_outer and the internal diameter is D_inner. We are given that the internal diameter is 0.6 times the external diameter, so we can write:

D_inner = 0.6 * D_outer

Now, let's calculate the cross-sectional areas of the solid and hollow sections.

Cross-sectional area of the solid section (A_solid) can be calculated using the formula for the area of a circle:

A_solid = π * (D_solid)^2 / 4

where D_solid is the diameter of the solid section, which is given as 50mm.

A_solid = π * (50^2) / 4 = 1963.5 mm^2

Cross-sectional area of the hollow section (A_hollow) can be calculated as the difference between the outer and inner circles:

A_hollow = π * (D_outer^2 - D_inner^2) / 4

Substituting the value of D_inner from the given relationship, we can simplify the equation:

A_hollow = π * (D_outer^2 - (0.6 * D_outer)^2) / 4
= π * (D_outer^2 - 0.36 * D_outer^2) / 4
= π * (0.64 * D_outer^2) / 4
= 0.16 * π * D_outer^2

Now, we need to equate the cross-sectional areas of the solid and hollow sections:

A_solid = A_hollow

1963.5 mm^2 = 0.16 * π * D_outer^2

Dividing both sides by 0.16 * π, we get:

D_outer^2 = 1963.5 mm^2 / (0.16 * π)
= 3100 mm^2 / π

Taking the square root of both sides, we find:

D_outer = √(3100 mm^2 / π)
≈ √988.23
≈ 31.4 mm

Now, substituting this value back into the equation for D_inner, we can find the internal diameter:

D_inner = 0.6 * D_outer
= 0.6 * 31.4 mm
≈ 18.8 mm

Therefore, the size of the hollow section is D_outer = 31.4 mm and D_inner = 18.8 mm.

The correct answer is option 'C': D_outer = 51.7 mm and D_inner = 31 mm.
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A solid circular compressionmember 50mm in diameter is to bereplaced by a hollow circularsection of the same material. Findthe size of hollow section if internaldiameter is 0.6 times external diameter.a)Douter = 40mm, Dinner = 24mmb)Douter = 63.1mm, Dinner = 37.86mmc)Douter = 51.7mm, Dinner = 31mmd)Douter = 71mm, Dinner = 42.6mmCorrect answer is option 'C'. Can you explain this answer?
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