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The angle of elevation of the top of a tower from a certain point is 30°. If the observer moves 40 m towards the tower, the angle of elevation of the top of the tower increases by 15°. The height of the tower is:
  • a)
    64.2 m
  • b)
    62.2 m
  • c)
    52.2 m
  • d)
    54.6 m
  • e)
    55.6 m
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The angle of elevation of the top of a tower from a certain point is 3...

Let DC be the tower and A and B be the positions of the observer such that AB = 40 m
We have ∠DAC = 30°, ∠DBC = 45°
Let DC = h

We know that,
AB = (AC − BC)
⇒ 40 = (AC − BC)

= 54.6 m
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