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A poster is on top of a building. Rajesh is standing on the ground at a distance of 50 m from the building. The angles of elevation to the top of the poster and bottom of the poster are 45° and 30° respectively. What is the height of the poster?
  • a)
    50(√3 - 1)/ √3 m
  • b)
    50√3 m
  • c)
    25/√3 m
  • d)
    25(√3 - 1)/ √3 m
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A poster is on top of a building. Rajesh is standing on the ground at ...

In ΔPNQ, Tan 45° = PQ/NQ
∴ PQ = NQ = 50m
In ΔMNQ, Tan 30° = MQ/NQ

∴ h = PM = PQ - MQ = 50 - 50/√3 = 50/√3 (√3 - 1) = Poster height
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