Rohit goes 7 km towards South-East from his house, then he goes 14 km ...
Given Information:
Rohit goes 7 km towards South-East from his house, then he goes 14 km turning to West. After this he goes 7 km towards North West and in the end he goes 9 km towards East.
To find: How far is Rohit from his house?
Solution:
Let us assume that Rohit's house is at point O.
From O, Rohit goes 7 km towards South-East which means he reaches point A.
From A, Rohit goes 14 km turning to West which means he reaches point B.
From B, Rohit goes 7 km towards North-West which means he reaches point C.
From C, Rohit goes 9 km towards East which means he reaches point D.
Now, we need to find the distance between point D and point O which will give us the distance between Rohit and his house.
Let's first draw the diagram:
[Insert image here]
From the diagram, we can see that ΔOAB is a right-angled triangle, where AB = 14 km and AO = 7 km.
Using the Pythagoras theorem, we can find BO which is the third side of the triangle.
(BO)² = (AB)² + (AO)²
(BO)² = (14)² + (7)²
(BO)² = 196 + 49
(BO)² = 245
BO = √245
BO = 7√5 km
Now, let's look at the triangle ΔBCD.
Here, CD = 9 km and BC = 7 km.
Again, using the Pythagoras theorem, we can find BD which is the third side of the triangle.
(BD)² = (CD)² + (BC)²
(BD)² = (9)² + (7)²
(BD)² = 81 + 49
(BD)² = 130
BD = √130 km
Finally, we need to find OD which is the distance between points D and O.
OD = BO + BD
OD = 7√5 + √130
OD ≈ 11.31 km
Therefore, Rohit is approximately 11.31 km away from his house.
Hence, the correct option is (d) 5 km.
Rohit goes 7 km towards South-East from his house, then he goes 14 km ...
To find the distance between Rohit's final position and his house, we can solve this problem using vector addition.
Step 1: Break down the directions and distances into components
- South-East: This direction can be broken down into two components, South and East.
- South: 7 * cos(45) = 7 * 0.707 = 4.95 km
- East: 7 * sin(45) = 7 * 0.707 = 4.95 km
- West: This direction has only one component, West.
- West: 14 km
- North-West: This direction can be broken down into two components, North and West.
- North: 7 * cos(45) = 7 * 0.707 = 4.95 km
- West: 7 * sin(45) = 7 * 0.707 = 4.95 km
- East: This direction has only one component, East.
- East: 9 km
Step 2: Add all the components
- Total South: 4.95 km
- Total East: 4.95 + 9 = 13.95 km
- Total North: 4.95 km
- Total West: 14 + 4.95 = 18.95 km
Step 3: Find the net displacement in North-South and East-West directions
- Net displacement in North-South direction: Total North - Total South = 4.95 - 4.95 = 0 km
- Net displacement in East-West direction: Total East - Total West = 13.95 - 18.95 = -5 km (negative sign indicates the direction is West)
Step 4: Calculate the distance
Since the net displacement in the North-South direction is 0 km, the total distance Rohit is from his house is the same as the net displacement in the East-West direction, which is 5 km (ignoring the negative sign as distance is always positive).
Answer: D. 5 km