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From a point Sahil starts walking in south-east direction. After walking for 6 m, he turned to west and walks another 10 m. Now he turned towards north-west and walks 6 m and then finally stopped after turning to east and walking 2 m. Find the distance from the starting point.
- a)10 m
- b)8 m
- c)12 m
- d)6 m
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
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From a point Sahil starts walking in south-east direction. Afte...
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From a point Sahil starts walking in south-east direction. Afte...
Given information:
● Starting direction: South-east
● Distance walked: 6 m towards south-east
● Turned towards: West
● Distance walked: 10 m towards west
● Turned towards: North-west
● Distance walked: 6 m towards north-west
● Stopped after turning towards: East
● Distance walked: 2 m towards east
To find: Distance from starting point
Approach:
We can draw the path followed by Sahil on a graph and then find the distance from the starting point using Pythagoras theorem.
Let's assume that Sahil starts from point A (0,0) and moves in the south-east direction for 6 m. So, his position now is at point B (6, -6).
Next, he turns towards the west and walks for 10 m. So, his position now is at point C (-4, -6).
Then, he turns towards the north-west direction and walks for 6 m. So, his position now is at point D (-10, 0).
Finally, he turns towards the east direction and walks for 2 m. So, his position now is at point E (-8, 0).
Now, we can use Pythagoras theorem to find the distance between points A and E, which is the distance from the starting point.
Distance = √((-8-0)^2 + (0-0)^2) = √64 = 8m
Therefore, the distance from the starting point is 8m.
Answer: (B) 8m.
● Starting direction: South-east
● Distance walked: 6 m towards south-east
● Turned towards: West
● Distance walked: 10 m towards west
● Turned towards: North-west
● Distance walked: 6 m towards north-west
● Stopped after turning towards: East
● Distance walked: 2 m towards east
To find: Distance from starting point
Approach:
We can draw the path followed by Sahil on a graph and then find the distance from the starting point using Pythagoras theorem.
Let's assume that Sahil starts from point A (0,0) and moves in the south-east direction for 6 m. So, his position now is at point B (6, -6).
Next, he turns towards the west and walks for 10 m. So, his position now is at point C (-4, -6).
Then, he turns towards the north-west direction and walks for 6 m. So, his position now is at point D (-10, 0).
Finally, he turns towards the east direction and walks for 2 m. So, his position now is at point E (-8, 0).
Now, we can use Pythagoras theorem to find the distance between points A and E, which is the distance from the starting point.
Distance = √((-8-0)^2 + (0-0)^2) = √64 = 8m
Therefore, the distance from the starting point is 8m.
Answer: (B) 8m.
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