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Consider three processes (process id 0, 1, 2 respectively) with compute time bursts 2, 4 and 8 time units. All processes arrive at time zero. Consider the longest remaining time first (LRTF) scheduling algorithm. In LRTF ties are broken by giving priority to the process with the lowest process id. The average turn around time is:
- a)13 units
- b)14 units
- c)15 units
- d)16 units
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Consider three processes (process id 0, 1, 2 respectively) with comput...
Let the processes be p0, p1 and p2. These processes will be executed in following order.
p2 p1 p2 p1 p2 p0 p1 p2 p0 p1 p2
0 4 5 6 7 8 9 10 11 12 13 14
Turn around time of a process is total time between submission of the process and its completion.
Turn around time of p0 = 12 (12-0)
Turn around time of p1 = 13 (13-0)
Turn around time of p2 = 14 (14-0)
Average turn around time is (12+13+14)/3 = 13.
Most Upvoted Answer
Consider three processes (process id 0, 1, 2 respectively) with comput...
Explanation:
To calculate the average turnaround time, we need to find the completion time for each process and then calculate the average. The completion time is the time at which a process finishes execution.
Process 0:
- Burst time: 2 units
- Arrival time: 0 units
Since process 0 has the shortest burst time and arrives first, it will be assigned the CPU first. The remaining burst time for process 0 is 0 units, so it completes execution at time 2.
Process 1:
- Burst time: 4 units
- Arrival time: 0 units
Process 1 arrives at time 0, but since process 0 is already running, it has to wait. The remaining burst time for process 1 is 2 units (4 - 2). Process 1 will be assigned the CPU after process 0 completes. The remaining burst time for process 1 is 0 units, so it completes execution at time 6.
Process 2:
- Burst time: 8 units
- Arrival time: 0 units
Process 2 arrives at time 0, but both process 0 and process 1 are already running. Process 2 has the longest burst time, so it has to wait. The remaining burst time for process 2 is 2 units (8 - 6). Process 2 will be assigned the CPU after process 1 completes. The remaining burst time for process 2 is 0 units, so it completes execution at time 14.
Calculating Turnaround Time:
Turnaround time for a process is the difference between its completion time and its arrival time.
Process 0:
- Completion time: 2 units
- Arrival time: 0 units
- Turnaround time: 2 - 0 = 2 units
Process 1:
- Completion time: 6 units
- Arrival time: 0 units
- Turnaround time: 6 - 0 = 6 units
Process 2:
- Completion time: 14 units
- Arrival time: 0 units
- Turnaround time: 14 - 0 = 14 units
Average Turnaround Time:
The average turnaround time is the sum of the turnaround times of all processes divided by the total number of processes.
Average Turnaround Time = (2 + 6 + 14) / 3 = 22 / 3 = 7.33 units
Since the given options are integers, we round up the average turnaround time to the nearest integer.
Final Answer:
The average turnaround time is 8 units.
To calculate the average turnaround time, we need to find the completion time for each process and then calculate the average. The completion time is the time at which a process finishes execution.
Process 0:
- Burst time: 2 units
- Arrival time: 0 units
Since process 0 has the shortest burst time and arrives first, it will be assigned the CPU first. The remaining burst time for process 0 is 0 units, so it completes execution at time 2.
Process 1:
- Burst time: 4 units
- Arrival time: 0 units
Process 1 arrives at time 0, but since process 0 is already running, it has to wait. The remaining burst time for process 1 is 2 units (4 - 2). Process 1 will be assigned the CPU after process 0 completes. The remaining burst time for process 1 is 0 units, so it completes execution at time 6.
Process 2:
- Burst time: 8 units
- Arrival time: 0 units
Process 2 arrives at time 0, but both process 0 and process 1 are already running. Process 2 has the longest burst time, so it has to wait. The remaining burst time for process 2 is 2 units (8 - 6). Process 2 will be assigned the CPU after process 1 completes. The remaining burst time for process 2 is 0 units, so it completes execution at time 14.
Calculating Turnaround Time:
Turnaround time for a process is the difference between its completion time and its arrival time.
Process 0:
- Completion time: 2 units
- Arrival time: 0 units
- Turnaround time: 2 - 0 = 2 units
Process 1:
- Completion time: 6 units
- Arrival time: 0 units
- Turnaround time: 6 - 0 = 6 units
Process 2:
- Completion time: 14 units
- Arrival time: 0 units
- Turnaround time: 14 - 0 = 14 units
Average Turnaround Time:
The average turnaround time is the sum of the turnaround times of all processes divided by the total number of processes.
Average Turnaround Time = (2 + 6 + 14) / 3 = 22 / 3 = 7.33 units
Since the given options are integers, we round up the average turnaround time to the nearest integer.
Final Answer:
The average turnaround time is 8 units.
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Consider three processes (process id 0, 1, 2 respectively) with compute time bursts 2, 4 and 8 time units. All processes arrive at time zero. Consider the longest remaining time first (LRTF) scheduling algorithm. In LRTF ties are broken by giving priority to the process with the lowest process id. The average turn around time is:a)13 unitsb)14 unitsc)15 unitsd)16 unitsCorrect answer is option 'A'. Can you explain this answer?
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