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If a =sqrt 3-sqrt 2/sqrt 3+sqrt 2 and b=sqrt 3+sqrt 2/sqrt 3-sqrt 2, find the value of a^2+b^2-5ab?
Most Upvoted Answer
If a =sqrt 3-sqrt 2/sqrt 3+sqrt 2 and b=sqrt 3+sqrt 2/sqrt 3-sqrt 2, f...
Calculating a and b values:

We need to calculate the values of a and b before proceeding with the main calculation.

a = (sqrt(3) - sqrt(2)) / (sqrt(3) * sqrt(2))

b = (sqrt(3) * sqrt(2)) / (sqrt(3) - sqrt(2))

Simplifying the above expressions will give us:

a = sqrt(3)/sqrt(2) - 1

b = sqrt(3)/sqrt(2) + 1

Calculating a^2 b^2:

a^2 b^2 can be calculated by simply squaring a and b and then multiplying them.

a^2 = (sqrt(3)/sqrt(2) - 1)^2 = 3/2 - 2sqrt(3)/2 + 1 = 5/2 - sqrt(3)

b^2 = (sqrt(3)/sqrt(2) + 1)^2 = 3/2 + 2sqrt(3)/2 + 1 = 5/2 + sqrt(3)

a^2 b^2 = (5/2 - sqrt(3)) * (5/2 + sqrt(3)) = 25/4 - 3

a^2 b^2 = 19/4

Calculating 5ab:

5ab can be calculated by multiplying 5 with the product of a and b.

5ab = 5 * (sqrt(3)/sqrt(2) - 1) * (sqrt(3)/sqrt(2) + 1)

5ab = 5 * ((3/2) - 1)

5ab = 5/2

Final Calculation:

Substituting the values of a^2 b^2 and 5ab in the given expression:

a^2 b^2 - 5ab = 19/4 - 5/2

a^2 b^2 - 5ab = -1/4

Therefore, the value of a^2 b^2 - 5ab is -1/4.
Community Answer
If a =sqrt 3-sqrt 2/sqrt 3+sqrt 2 and b=sqrt 3+sqrt 2/sqrt 3-sqrt 2, f...
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