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How many gm of I2 are present in a solution which requires 40 ml of 0.11N Na2S2O3 to react with it via the reaction : S2O32– + I2 → S4O62– + 2I– ?
- a)12.7g
- b)0.558g
- c)25.4g
- d)11.4g
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
How many gm of I2 are present in a solution which requires 40 ml of 0....
Meq. of I2 = Meq. of Na2S2O3 = 40 × 0.11
∴ (W × 2 × 1000)/254 = 40 × 0.11
W of I2 = 0.558g
∴ (W × 2 × 1000)/254 = 40 × 0.11
W of I2 = 0.558g
Most Upvoted Answer
How many gm of I2 are present in a solution which requires 40 ml of 0....
Yes ans is B.normality = M × nfso Molarity = 0.11apply formulM × V(in litre)× nf = n × nfso , 0.11× 0.04 × 1 = n × 2n = 0.002 wt = 0.002×253.80 = 0.558g
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Community Answer
How many gm of I2 are present in a solution which requires 40 ml of 0....
To determine the grams of I2 present in the solution, we need to use the stoichiometry of the reaction between I2 and Na2S2O3.
The balanced chemical equation for the reaction is:
I2 + 2Na2S2O3 → 2NaI + Na2S4O6
From the equation, we can see that 1 mole of I2 reacts with 2 moles of Na2S2O3.
First, let's calculate the number of moles of Na2S2O3 used in the reaction:
Moles of Na2S2O3 = (volume in liters) x (molarity)
Moles of Na2S2O3 = (40 ml / 1000 ml/L) x 0.11 mol/L
Moles of Na2S2O3 = 0.0044 mol
Since the stoichiometry of the reaction is 1:1 for I2 and Na2S2O3, the number of moles of I2 present in the solution is also 0.0044 mol.
Now, let's calculate the molar mass of I2:
Molar mass of I2 = 2 x atomic mass of I
Molar mass of I2 = 2 x 126.90 g/mol
Molar mass of I2 = 253.80 g/mol
Finally, we can calculate the grams of I2 present in the solution:
Grams of I2 = Moles of I2 x Molar mass of I2
Grams of I2 = 0.0044 mol x 253.80 g/mol
Grams of I2 = 1.115 g
Therefore, there are 1.115 grams of I2 present in the solution.
The balanced chemical equation for the reaction is:
I2 + 2Na2S2O3 → 2NaI + Na2S4O6
From the equation, we can see that 1 mole of I2 reacts with 2 moles of Na2S2O3.
First, let's calculate the number of moles of Na2S2O3 used in the reaction:
Moles of Na2S2O3 = (volume in liters) x (molarity)
Moles of Na2S2O3 = (40 ml / 1000 ml/L) x 0.11 mol/L
Moles of Na2S2O3 = 0.0044 mol
Since the stoichiometry of the reaction is 1:1 for I2 and Na2S2O3, the number of moles of I2 present in the solution is also 0.0044 mol.
Now, let's calculate the molar mass of I2:
Molar mass of I2 = 2 x atomic mass of I
Molar mass of I2 = 2 x 126.90 g/mol
Molar mass of I2 = 253.80 g/mol
Finally, we can calculate the grams of I2 present in the solution:
Grams of I2 = Moles of I2 x Molar mass of I2
Grams of I2 = 0.0044 mol x 253.80 g/mol
Grams of I2 = 1.115 g
Therefore, there are 1.115 grams of I2 present in the solution.
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How many gm of I2 are present in a solution which requires 40 ml of 0.11N Na2S2O3 to react with it via the reaction : S2O32– + I2 → S4O62– + 2I– ?a)12.7gb)0.558gc)25.4gd)11.4gCorrect answer is option 'B'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about How many gm of I2 are present in a solution which requires 40 ml of 0.11N Na2S2O3 to react with it via the reaction : S2O32– + I2 → S4O62– + 2I– ?a)12.7gb)0.558gc)25.4gd)11.4gCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many gm of I2 are present in a solution which requires 40 ml of 0.11N Na2S2O3 to react with it via the reaction : S2O32– + I2 → S4O62– + 2I– ?a)12.7gb)0.558gc)25.4gd)11.4gCorrect answer is option 'B'. Can you explain this answer?.
How many gm of I2 are present in a solution which requires 40 ml of 0.11N Na2S2O3 to react with it via the reaction : S2O32– + I2 → S4O62– + 2I– ?a)12.7gb)0.558gc)25.4gd)11.4gCorrect answer is option 'B'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about How many gm of I2 are present in a solution which requires 40 ml of 0.11N Na2S2O3 to react with it via the reaction : S2O32– + I2 → S4O62– + 2I– ?a)12.7gb)0.558gc)25.4gd)11.4gCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many gm of I2 are present in a solution which requires 40 ml of 0.11N Na2S2O3 to react with it via the reaction : S2O32– + I2 → S4O62– + 2I– ?a)12.7gb)0.558gc)25.4gd)11.4gCorrect answer is option 'B'. Can you explain this answer?.
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