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How many gm of I2 are present in a solution which requires 40 ml of 0.11N Na2S2O3 to react with it via the reaction :  S2O32– + I2 → S4O62– + 2I ?
  • a)
    12.7g
  • b)
    0.558g
  • c)
    25.4g
  • d)
    11.4g
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
How many gm of I2 are present in a solution which requires 40 ml of 0....
Meq. of I= Meq. of Na2S2O3 = 40 × 0.11
∴ (W × 2 × 1000)/254  = 40 × 0.11
W of I= 0.558g
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Most Upvoted Answer
How many gm of I2 are present in a solution which requires 40 ml of 0....
Yes ans is B.normality = M × nfso Molarity = 0.11apply formulM × V(in litre)× nf = n × nfso , 0.11× 0.04 × 1 = n × 2n = 0.002 wt = 0.002×253.80 = 0.558g
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Community Answer
How many gm of I2 are present in a solution which requires 40 ml of 0....
 
Meq.of I= Meq.of Na2S2O3
= 40×0.11
∴ w/254/2×1000
=40×0.11
wI2=0.558g
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