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In a consecutive first order reaction,
(where k1 and k2 are the respective rate constants) species B has transient existence. Therefore,
- a)k1 ≈ k2
- b)k1 = 2 k2
- c)k1 >> k2
- d)k1 << k2
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In a consecutive first order reaction,(where k1 and k2 are the respect...
We cannot determine the values of k1 and k2 based on the given information.
However, we can make some observations based on the fact that species B has a transient existence.
In a consecutive first order reaction, the reaction mechanism involves a series of consecutive steps, each with its own rate constant. Species B is likely an intermediate that is formed in the first step and consumed in the second step.
If species B has a very short lifespan, it means that the second step is much faster than the first step. This implies that k2 is much larger than k1.
We can also say that the concentration of species B at any given time is proportional to k1/k2. This is because the rate of formation of B is proportional to k1[A], while the rate of consumption of B is proportional to k2[B]. At equilibrium, the rate of formation of B equals the rate of consumption of B, so k1[A] = k2[B]. Solving for [B] gives [B] = k1/k2 [A].
In summary, we cannot determine the values of k1 and k2, but we can say that k2 is much larger than k1 and that the concentration of species B is proportional to k1/k2.
However, we can make some observations based on the fact that species B has a transient existence.
In a consecutive first order reaction, the reaction mechanism involves a series of consecutive steps, each with its own rate constant. Species B is likely an intermediate that is formed in the first step and consumed in the second step.
If species B has a very short lifespan, it means that the second step is much faster than the first step. This implies that k2 is much larger than k1.
We can also say that the concentration of species B at any given time is proportional to k1/k2. This is because the rate of formation of B is proportional to k1[A], while the rate of consumption of B is proportional to k2[B]. At equilibrium, the rate of formation of B equals the rate of consumption of B, so k1[A] = k2[B]. Solving for [B] gives [B] = k1/k2 [A].
In summary, we cannot determine the values of k1 and k2, but we can say that k2 is much larger than k1 and that the concentration of species B is proportional to k1/k2.
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In a consecutive first order reaction,(where k1 and k2 are the respect...
When a species exist in the transient state it means it's formation requires a slow process but after the formation of transient state the reaction is faster so k2>>k1
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In a consecutive first order reaction,(where k1 and k2 are the respective rate constants) species B has transient existence. Therefore,a)k1 ≈ k2b)k1 = 2 k2c)k1 >> k2d)k1 << k2Correct answer is option 'D'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In a consecutive first order reaction,(where k1 and k2 are the respective rate constants) species B has transient existence. Therefore,a)k1 ≈ k2b)k1 = 2 k2c)k1 >> k2d)k1 << k2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a consecutive first order reaction,(where k1 and k2 are the respective rate constants) species B has transient existence. Therefore,a)k1 ≈ k2b)k1 = 2 k2c)k1 >> k2d)k1 << k2Correct answer is option 'D'. Can you explain this answer?.
In a consecutive first order reaction,(where k1 and k2 are the respective rate constants) species B has transient existence. Therefore,a)k1 ≈ k2b)k1 = 2 k2c)k1 >> k2d)k1 << k2Correct answer is option 'D'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In a consecutive first order reaction,(where k1 and k2 are the respective rate constants) species B has transient existence. Therefore,a)k1 ≈ k2b)k1 = 2 k2c)k1 >> k2d)k1 << k2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a consecutive first order reaction,(where k1 and k2 are the respective rate constants) species B has transient existence. Therefore,a)k1 ≈ k2b)k1 = 2 k2c)k1 >> k2d)k1 << k2Correct answer is option 'D'. Can you explain this answer?.
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