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A solid is formed and it has three types of atoms X, Y, Z. X forms a FCC lattice with Y atoms occupying all the tetrahedral voids and Z atoms occupying half the octahedral voids. The formula of the solid is:
  • a)
    X2Y4Z
  • b)
    XY2Z4
  • c)
    X4YZ2
  • d)
    none
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A solid is formed and it has three types of atoms X, Y, Z. X forms a F...
In an fcc unit cell, there are 4 atoms in one unit cell. X forms fcc lattice. Hence, number of X atoms in unit cell = 4. Y atoms occupies all tetrahedral voids. In fcc unit cell, there are 8 tetrahedral voids. Hence, number of Y atoms in unit cell = 8. Z atoms occupy half the octahedral voids. In fcc unit cell, there are 4 octahedral voids. 
Hence, number of Z atoms = 4/2 =2
Hence, the ratio X:Y:Z =4:8:2 or 2:4:1 Hence, the formula of the solid is X2Y4Z
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Most Upvoted Answer
A solid is formed and it has three types of atoms X, Y, Z. X forms a F...
Explanation:
The given solid has three types of atoms X, Y, Z. X forms a FCC (Face-centered cubic) lattice. Y atoms occupy all the tetrahedral voids and Z atoms occupy half the octahedral voids.

FCC Lattice:
In an FCC lattice, the atoms are arranged in a cubic close-packed structure with one atom at each corner and one atom in the center of each face of the cube. This arrangement gives a coordination number of 12 for each atom.

Tetrahedral Voids:
In a FCC lattice, there are tetrahedral voids located between the four atoms that form a tetrahedron. These voids have a coordination number of 4 and are occupied by smaller atoms.

Octahedral Voids:
In a FCC lattice, there are octahedral voids located between the six atoms that form an octahedron. These voids have a coordination number of 6 and are occupied by smaller atoms.

Formula of the Solid:
X forms a FCC lattice, so the formula will start with X. Y atoms occupy all the tetrahedral voids. In a FCC lattice, there are twice as many tetrahedral voids as there are atoms, so the formula will have 4Y. Z atoms occupy half the octahedral voids. In a FCC lattice, there is one octahedral void for each atom, so the formula will have 2Z. Therefore, the formula of the solid is X2Y4Z.

Answer:
The correct answer is option 'A' (X2Y4Z).
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A solid is formed and it has three types of atoms X, Y, Z. X forms a FCC lattice with Y atoms occupying all the tetrahedral voids and Z atoms occupying half the octahedral voids. The formula of the solid is:a)X2Y4Zb)XY2Z4c)X4YZ2d)noneCorrect answer is option 'A'. Can you explain this answer?
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