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For a given first order reaction, the reactant reduces to 1/4th its initial value in 10 min. The rate constant of the reaction is:
  • a)
    0.1386 min–1
  • b)
    0.0693 min–1
  • c)
    0.1386 mol L–1 min–1
  • d)
    0.0693 mol L–1 min–1
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
For a given first order reaction, the reactant reduces to 1/4th its in...
To solve this problem, we can use the first-order reaction equation:

ln([A]/[A]0) = -kt

where [A] is the concentration of the reactant at time t, [A]0 is the initial concentration, k is the rate constant, and t is time.

We know that [A]/[A]0 = 1/4, since the reactant reduces to 1/4th its initial value. We also know that t = 10 min. Substituting these values into the equation, we get:

ln(1/4) = -k(10)

Solving for k, we get:

k = ln(1/4)/(-10) = 0.1386 min^-1

Therefore, the rate constant of the reaction is 0.1386 min^-1.
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Community Answer
For a given first order reaction, the reactant reduces to 1/4th its in...
Use formula of 1st order reaction and put (a-x)=a/4
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For a given first order reaction, the reactant reduces to 1/4th its initial value in 10 min. The rate constant of the reaction is:a)0.1386 min–1b)0.0693 min–1c)0.1386 mol L–1 min–1d)0.0693 mol L–1 min–1Correct answer is option 'A'. Can you explain this answer?
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For a given first order reaction, the reactant reduces to 1/4th its initial value in 10 min. The rate constant of the reaction is:a)0.1386 min–1b)0.0693 min–1c)0.1386 mol L–1 min–1d)0.0693 mol L–1 min–1Correct answer is option 'A'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about For a given first order reaction, the reactant reduces to 1/4th its initial value in 10 min. The rate constant of the reaction is:a)0.1386 min–1b)0.0693 min–1c)0.1386 mol L–1 min–1d)0.0693 mol L–1 min–1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a given first order reaction, the reactant reduces to 1/4th its initial value in 10 min. The rate constant of the reaction is:a)0.1386 min–1b)0.0693 min–1c)0.1386 mol L–1 min–1d)0.0693 mol L–1 min–1Correct answer is option 'A'. Can you explain this answer?.
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