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The full-load copper losses and iron losses of a transformer are 6400 W and 5000 Wrespectively. The copper loss and iron loss at half full-load will be respectively.
  • a)
    3200 W and 2500 W
  • b)
    1600 W and 5000 W
  • c)
    3200 W and 5200 W
  • d)
    1600 W and 1250 W
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The full-load copper losses and iron losses of a transformer are 6400 ...
Calculation of Copper and Iron Losses
Given,
Full-load copper losses = 6400 W
Iron losses = 5000 W
Let's assume that the transformer has a full load of 1000 W.
Therefore, the total losses in the transformer = Copper losses + Iron losses.
Total losses = 6400 W + 5000 W = 11400 W
Now, if the transformer is loaded at half the full load, i.e. 500 W, then the losses can be calculated as follows:

Copper Losses at Half Full-Load
Copper losses are proportional to the square of the current. Therefore, at half the full-load, the current will be halved, and the copper losses will be reduced to 1/4th of the full-load copper losses.
Copper losses at half full-load = (1/4) x Full-load copper losses
Copper losses at half full-load = (1/4) x 6400 W
Copper losses at half full-load = 1600 W

Iron Losses at Half Full-Load
Iron losses are constant and do not depend on the load. Therefore, the iron losses at half full-load will be the same as the iron losses at full-load.
Iron losses at half full-load = Iron losses at full-load
Iron losses at half full-load = 5000 W

Therefore, the copper loss and iron loss at half full-load will be 1600 W and 5000 W respectively, which is option B.
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Community Answer
The full-load copper losses and iron losses of a transformer are 6400 ...
Because iron loss is same for all whereas copper loss is in ratio of (1/2,)
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The full-load copper losses and iron losses of a transformer are 6400 W and 5000 Wrespectively. The copper loss and iron loss at half full-load will be respectively.a)3200 W and 2500 Wb)1600 W and 5000 Wc)3200 W and 5200 Wd)1600 W and 1250 WCorrect answer is option 'B'. Can you explain this answer?
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