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The sum of the digits of a two digit number is 12. The number obtained by reversing its digits exceeds the given number by 18. Then the number is_____
  • a)
    75
  • b)
    25
  • c)
    52
  • d)
    57
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The sum of the digits of a two digit number is 12. The number obtained...
Let us assume x and y are the two digits of the number
Therefore, two-digit number is = 10x + y and the reversed number = 10y + x
Given:
x + y = 12
y = 12 – x  (1)
Also given:
10y + x - 10x – y = 18
9y – 9x = 18
y – x = 2    (2)
Substitute the value of y from eqn 1 in eqn 2
12 – x – x = 2
12 – 2x = 2
2x = 10
x = 5
Therefore, y = 12 – x = 12 – 5 = 7
Therefore, the two-digit number is 10x + y = (10*5) + 7 = 57
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Most Upvoted Answer
The sum of the digits of a two digit number is 12. The number obtained...
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Community Answer
The sum of the digits of a two digit number is 12. The number obtained...
Let ,one is x & another is y,
x+y =12. 1
and
10y + x = 10x +y+18. 2
Now solve
solving 2
9(x-y)=18
x-y = 2. 3
adding 1&3
we get,
2x=14
so,x=7
putting X's value in 1
we get y= 5


Required ni:- 57
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The sum of the digits of a two digit number is 12. The number obtained by reversing its digits exceeds the given number by 18. Then the number is_____a)75b)25c)52d)57Correct answer is option 'D'. Can you explain this answer?
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