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The multiplying factor, as applied to obtain the maximum daily water demand, in relation to the average i.e. per capita daily demand, is
  • a)
    1.5
  • b)
    1.8
  • c)
    2.0
  • d)
    2.7
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The multiplying factor, as applied to obtain the maximum daily water d...
M.D.D = 1.8 x q
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The multiplying factor, as applied to obtain the maximum daily water d...
The multiplying factor, as applied to obtain the maximum daily water demand, in relation to the average i.e. per capita daily demand is 1.8.

Explanation:

- The average or per capita daily demand is the average amount of water that an individual consumes in a day, which is usually estimated to be around 135 liters per day.
- However, the maximum daily water demand is not just the sum of all individual demands, but it also includes additional demands from commercial, industrial, institutional, and other non-residential users.
- To account for these additional demands, a multiplying factor is applied to the average or per capita daily demand to obtain the maximum daily water demand.
- The multiplying factor varies depending on the type of area, population density, and other factors, but it is generally around 1.8.
- This means that the maximum daily water demand is approximately 1.8 times the average or per capita daily demand.

Example:

- If the average or per capita daily demand is 135 liters per day, then the maximum daily water demand would be approximately 243 liters per day (135 x 1.8).
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Community Answer
The multiplying factor, as applied to obtain the maximum daily water d...
Maximum water demand is 1.8 times of avg daily demand and 1.5 times of max hourly demand=1.5* avg hourly water demand
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The multiplying factor, as applied to obtain the maximum daily water demand, in relation to the average i.e. per capita daily demand, isa)1.5b)1.8c)2.0d)2.7Correct answer is option 'B'. Can you explain this answer?
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