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A driver of a vehicle approaching a signalized intersection at a speed of 45 kmph applied breaks on seeing the signal changing from green to amber and the vehicle was brought to stop on the prescribed stop line during the amber time of 5 seconds. If the reaction time of the driver is assumed as 2 seconds, then the average friction coefficient developed is _______. (up to 3 decimal place)
(Assume, length of vehicle = 6 m and width of road = 7 m)
Correct answer is between '0.32,0.33'. Can you explain this answer?
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Verified Answer
A driver of a vehicle approaching a signalized intersection at a speed...
Concept:
Interval design (most critical time)
There are two intervals, namely the change interval and clearance interval.
The purpose of these intervals is to warn a driver approaching the intersection during the end of a green time about the coming of a red signal. At this moment driver has two choices either to stop before the intersection or to clear the intersection. Amber time is provided such that at least one of these opportunities is available to the driver irrespective of driver position.
If the minimum amber time provided is Tmin.
Then the distance covered by the driver moving with design speed is
= V × Tmin
Also,
V × Tmin = dc + W + L
dc = V × Tmin – W – L
dc = < x < ds (SSD)
x is the zone of the dilemma
Where V = speed of the vehicle
SSD = stopping sight distance
W = width of the road
L = length of the vehicle
To avoid this dilemma
Calculation:
Given:
V = 45 kmph = 12.5 m/s
Amber time = 5 sec.
Reaction time = 2 sec.
⇒ f = 0.325
Most Upvoted Answer
A driver of a vehicle approaching a signalized intersection at a speed...
Given:
- Speed of the vehicle = 45 kmph
- Reaction time of the driver = 2 seconds
- Amber time = 5 seconds
- Length of the vehicle = 6 m
- Width of the road = 7 m
To find:
The average friction coefficient developed by the vehicle.
Formula:
The average friction coefficient can be calculated using the equation:
Friction Coefficient = (2 * acceleration) / (g * cosθ)
Where,
- acceleration = (final velocity - initial velocity) / time
- g = acceleration due to gravity = 9.81 m/s²
- θ = angle of inclination of the road (assumed to be 0°)
Calculations:
1. Convert the speed of the vehicle from kmph to m/s:
Speed = 45 kmph = (45 * 1000) / 3600 = 12.5 m/s
2. Calculate the distance covered during the reaction time:
Distance = Speed * Reaction time = 12.5 * 2 = 25 m
3. Calculate the distance covered during the amber time:
Distance = Speed * Time = 12.5 * 5 = 62.5 m
4. Calculate the total distance covered by the vehicle:
Total Distance = Distance covered during reaction time + Distance covered during amber time
= 25 + 62.5 = 87.5 m
5. Calculate the initial velocity of the vehicle:
Initial Velocity = 0 m/s (assuming the vehicle was initially at rest)
6. Calculate the final velocity of the vehicle:
Final Velocity = 0 m/s (since the vehicle was brought to a stop)
7. Calculate the time taken to bring the vehicle to stop during the amber time:
Time = Amber time = 5 seconds
8. Calculate the acceleration of the vehicle:
Acceleration = (Final Velocity - Initial Velocity) / Time
= (0 - 12.5) / 5
= -2.5 m/s² (negative sign indicates deceleration)
9. Calculate the average friction coefficient:
Friction Coefficient = (2 * Acceleration) / (g * cosθ)
= (2 * (-2.5)) / (9.81 * 1)
= -0.509
Since the friction coefficient cannot be negative, we take its magnitude:
Friction Coefficient = 0.509
Answer:
The average friction coefficient developed by the vehicle is 0.509.
- Speed of the vehicle = 45 kmph
- Reaction time of the driver = 2 seconds
- Amber time = 5 seconds
- Length of the vehicle = 6 m
- Width of the road = 7 m
To find:
The average friction coefficient developed by the vehicle.
Formula:
The average friction coefficient can be calculated using the equation:
Friction Coefficient = (2 * acceleration) / (g * cosθ)
Where,
- acceleration = (final velocity - initial velocity) / time
- g = acceleration due to gravity = 9.81 m/s²
- θ = angle of inclination of the road (assumed to be 0°)
Calculations:
1. Convert the speed of the vehicle from kmph to m/s:
Speed = 45 kmph = (45 * 1000) / 3600 = 12.5 m/s
2. Calculate the distance covered during the reaction time:
Distance = Speed * Reaction time = 12.5 * 2 = 25 m
3. Calculate the distance covered during the amber time:
Distance = Speed * Time = 12.5 * 5 = 62.5 m
4. Calculate the total distance covered by the vehicle:
Total Distance = Distance covered during reaction time + Distance covered during amber time
= 25 + 62.5 = 87.5 m
5. Calculate the initial velocity of the vehicle:
Initial Velocity = 0 m/s (assuming the vehicle was initially at rest)
6. Calculate the final velocity of the vehicle:
Final Velocity = 0 m/s (since the vehicle was brought to a stop)
7. Calculate the time taken to bring the vehicle to stop during the amber time:
Time = Amber time = 5 seconds
8. Calculate the acceleration of the vehicle:
Acceleration = (Final Velocity - Initial Velocity) / Time
= (0 - 12.5) / 5
= -2.5 m/s² (negative sign indicates deceleration)
9. Calculate the average friction coefficient:
Friction Coefficient = (2 * Acceleration) / (g * cosθ)
= (2 * (-2.5)) / (9.81 * 1)
= -0.509
Since the friction coefficient cannot be negative, we take its magnitude:
Friction Coefficient = 0.509
Answer:
The average friction coefficient developed by the vehicle is 0.509.
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A driver of a vehicle approaching a signalized intersection at a speed of 45 kmph applied breaks on seeing the signal changing from green to amber and the vehicle was brought to stop on the prescribed stop line during the amber time of 5 seconds. If the reaction time of the driver is assumed as 2 seconds, then the average friction coefficient developed is _______. (up to 3 decimal place)(Assume, length of vehicle = 6 m and width of road = 7 m)Correct answer is between '0.32,0.33'. Can you explain this answer?
Question Description
A driver of a vehicle approaching a signalized intersection at a speed of 45 kmph applied breaks on seeing the signal changing from green to amber and the vehicle was brought to stop on the prescribed stop line during the amber time of 5 seconds. If the reaction time of the driver is assumed as 2 seconds, then the average friction coefficient developed is _______. (up to 3 decimal place)(Assume, length of vehicle = 6 m and width of road = 7 m)Correct answer is between '0.32,0.33'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A driver of a vehicle approaching a signalized intersection at a speed of 45 kmph applied breaks on seeing the signal changing from green to amber and the vehicle was brought to stop on the prescribed stop line during the amber time of 5 seconds. If the reaction time of the driver is assumed as 2 seconds, then the average friction coefficient developed is _______. (up to 3 decimal place)(Assume, length of vehicle = 6 m and width of road = 7 m)Correct answer is between '0.32,0.33'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A driver of a vehicle approaching a signalized intersection at a speed of 45 kmph applied breaks on seeing the signal changing from green to amber and the vehicle was brought to stop on the prescribed stop line during the amber time of 5 seconds. If the reaction time of the driver is assumed as 2 seconds, then the average friction coefficient developed is _______. (up to 3 decimal place)(Assume, length of vehicle = 6 m and width of road = 7 m)Correct answer is between '0.32,0.33'. Can you explain this answer?.
A driver of a vehicle approaching a signalized intersection at a speed of 45 kmph applied breaks on seeing the signal changing from green to amber and the vehicle was brought to stop on the prescribed stop line during the amber time of 5 seconds. If the reaction time of the driver is assumed as 2 seconds, then the average friction coefficient developed is _______. (up to 3 decimal place)(Assume, length of vehicle = 6 m and width of road = 7 m)Correct answer is between '0.32,0.33'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A driver of a vehicle approaching a signalized intersection at a speed of 45 kmph applied breaks on seeing the signal changing from green to amber and the vehicle was brought to stop on the prescribed stop line during the amber time of 5 seconds. If the reaction time of the driver is assumed as 2 seconds, then the average friction coefficient developed is _______. (up to 3 decimal place)(Assume, length of vehicle = 6 m and width of road = 7 m)Correct answer is between '0.32,0.33'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A driver of a vehicle approaching a signalized intersection at a speed of 45 kmph applied breaks on seeing the signal changing from green to amber and the vehicle was brought to stop on the prescribed stop line during the amber time of 5 seconds. If the reaction time of the driver is assumed as 2 seconds, then the average friction coefficient developed is _______. (up to 3 decimal place)(Assume, length of vehicle = 6 m and width of road = 7 m)Correct answer is between '0.32,0.33'. Can you explain this answer?.
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