Solar radiation of 1200 W/m2 falls perpendicularly on a grey opaquesurface of emissivity 0.5. If the surface temperature is 50°C and surfaceemissive power 600 W/m2, the radiosity of that surface will be: 
  • a)
    600 W/m2
  • b)
    1000 W/m2
  • c)
    1200 W/m2
  • d)
    1800 W/m2
Correct answer is option 'C'. Can you explain this answer?

Mechanical Engineering Question

Aakash Pandey answered Jul 16, 2018
We know that radiosity is the total amount of radiation leaving the surface, given as sum of emissive power
of surface and amount reflected solar radiation, so we have

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