Which one of the following ions has the highest value of ionic radius ? [AIEEE-2004]a)O2-b)B3+c)Li+d)F-Correct answer is option 'A'. Can you explain this answer?

Question

Answer

This can be explained on the basis of z/e, where as z/e ratio increases, the size decreases and when z/e ratio decreases the size increases.

z is atomic number and e is number of electrons.

For Li⁺, z/e = 3/2 = 1.5

For F^-, z/e = 9/10 = 0.9

For O^2-, z/e = 8/10 = 0.8

For B³⁺, z/e = 5/2 = 2.5

The correct option is A.

Answer

The ionic radius of negative ion in greater than positive ion. Thus ionic radius order is B+³

Answer

Because greater will be negative charge greater will be radius of ion

Answer

Explanation:

Definition of ionic radius:
Ionic radius is defined as the radius of an ion in an ionic compound.

Factors affecting ionic radius:
1. Number of electron shells: More the number of electron shells, larger the ionic radius.
2. Nuclear charge: Greater the nuclear charge, smaller the ionic radius.
3. Electron-electron repulsions: Repulsions between electrons in the same shell cause the ionic radius to increase.

Comparison of ions:
- O2- ion has the highest value of ionic radius among the given options.
- O2- has 10 electrons and a charge of -2. Due to the addition of two extra electrons, the electron-electron repulsions increase, causing the ionic radius to increase.
- B3+ has 3 electrons and a charge of +3, resulting in a smaller ionic radius due to the higher nuclear charge.
- Li+ has 3 electrons and a charge of +1, leading to a smaller ionic radius compared to O2-.
- F- has 10 electrons and a charge of -1, but the ionic radius of F- is smaller than O2- due to the higher nuclear charge of fluorine.

Therefore, O2- ion has the highest value of ionic radius among the given ions due to the electron-electron repulsions caused by the addition of extra electrons.

Answer

In isoelectronic species, higher the negative charge on the atom, higher will be the radius

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