xa–b × xb–c × xc–a is equal toa)xb)1c)0d)n...
Explanation:
The sum of the angles of a triangle is always 180°. Using this property, we can easily find the value of xab, xbc, and xca.
Let's consider the triangle ABC:
Angle BAC = xca
Angle ABC = xbc
Angle BCA = xab
Using the property that the sum of the angles of a triangle is 180°, we get:
xab + xbc + xca = 180°
Therefore, the sum of the angles xab, xbc, and xca is equal to 180°.
But we know that xab, xbc, and xca are angles of a triangle. The sum of the angles of a triangle is also 180°. Therefore, we can conclude that:
x + x + x = 180°
Simplifying the above equation, we get:
3x = 180°
Dividing both sides by 3, we get:
x = 60°
Now, we can substitute the value of x in the equation xab + xbc + xca = 180°:
xab + xbc + xca = 180°
60° + 60° + 60° = 180°
Therefore, xab, xbc, and xca are all equal to 60°.
Now, we can calculate the value of xab * xbc * xca:
xab * xbc * xca = 60° * 60° * 60°
xab * xbc * xca = 216,000°
Since 216,000° is not equal to 1 or 0, the correct answer is option 'D' - none of these.
Therefore, the correct answer to the given question is option 'D' - none of these.
xa–b × xb–c × xc–a is equal toa)xb)1c)0d)n...
X^a-b+b-c+c-a x^a-a+b-b+c-c x^0 =1
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