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The decreasing value of bond angles from NH3 (106)° to SbH3 (101)° down group-15 of the periodic table is due to:                                                                                                                              [AIEEE-2006]
  • a)
     Decreasing lp – bp repulsion
  • b)
    Increasing electronegativity
  • c)
    Increasing bp – bp repulsion
  • d)
    Increasing p–orbital character in sp3
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The decreasing value of bond angles from NH3(106)° to SbH3(101)&de...
Answer is decreasing Electronegativity:


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The decreasing value of bond angles from NH3(106)° to SbH3(101)° down group-15 of the periodic table is due to: [AIEEE-2006]a)Decreasing lp –bp repulsionb)Increasing electronegativityc)Increasing bp –bp repulsiond)Increasing p–orbital character in sp3Correct answer is option 'D'. Can you explain this answer?
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The decreasing value of bond angles from NH3(106)° to SbH3(101)° down group-15 of the periodic table is due to: [AIEEE-2006]a)Decreasing lp –bp repulsionb)Increasing electronegativityc)Increasing bp –bp repulsiond)Increasing p–orbital character in sp3Correct answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The decreasing value of bond angles from NH3(106)° to SbH3(101)° down group-15 of the periodic table is due to: [AIEEE-2006]a)Decreasing lp –bp repulsionb)Increasing electronegativityc)Increasing bp –bp repulsiond)Increasing p–orbital character in sp3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The decreasing value of bond angles from NH3(106)° to SbH3(101)° down group-15 of the periodic table is due to: [AIEEE-2006]a)Decreasing lp –bp repulsionb)Increasing electronegativityc)Increasing bp –bp repulsiond)Increasing p–orbital character in sp3Correct answer is option 'D'. Can you explain this answer?.
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