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The correct order of ionic size of N3–, Na+, F, Mg2+ and O2– is:
  • a)
    Mg2+ > Na+ > F > O2– < N3–
  • b)
    N3– < F > O2– > Na+ > Mg2+
  • c)
    Mg2+ < Na+ < F < O2– < N3–
  • d)
    N3– > O2– > F > Na+ < Mg2+
Correct answer is option 'C'. Can you explain this answer?
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The correct order of ionic size of N3–, Na+, F–, Mg2+ and ...
If the ions derived from different atoms are isoelectronic species, then they all have same number of electrons in their electronic shells and will have got same electronic configuration but their nuclear charge will differ because of their difference in number of protons in the nucleus. With increase in number of protonsin the nucleus the electrons are more attracted towards nucleus thereby causing the decrease in ionic radius. On this principle our problem will be solved
The given ions are
  • 7N3-→no. of proton=7 and no of electron=10
  • 8O2-→no. of proton=8 and no of electron=10
  • 9F-→no. of proton=9 and no of electron=10
  • 11Na+→no. of proton=11 and no of electron=10
  • 12Mg2+→no. of proton=12 and no of electron=10
Hence the increasing order of ionic radius is
12Mg2+11Na+9F-8O2-7N3-
For isoelectronic species lower the nuclear charge higher the radius
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The correct order of ionic size of N3–, Na+, F–, Mg2+ and ...
The correct order of ionic size for N3- is as follows:

1. N3- < o2-="" />< f-="" />< na+="" />< mg2+="" />< />

This order is based on the trend that as you move across a period from left to right, the atomic radius decreases. Additionally, as you move down a group, the atomic radius increases. Therefore, N3- has a smaller ionic size than O2-, F-, Na+, Mg2+, and Al3+.
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The correct order of ionic size of N3–, Na+, F–, Mg2+ and ...
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The correct order of ionic size of N3–, Na+, F–, Mg2+ and O2– is:a)Mg2+ > Na+ > F– > O2– < N3–b)N3– < F– > O2– > Na+ > Mg2+c)Mg2+ < Na+ < F– < O2– < N3–d)N3– > O2– > F– > Na+ < Mg2+Correct answer is option 'C'. Can you explain this answer?
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The correct order of ionic size of N3–, Na+, F–, Mg2+ and O2– is:a)Mg2+ > Na+ > F– > O2– < N3–b)N3– < F– > O2– > Na+ > Mg2+c)Mg2+ < Na+ < F– < O2– < N3–d)N3– > O2– > F– > Na+ < Mg2+Correct answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The correct order of ionic size of N3–, Na+, F–, Mg2+ and O2– is:a)Mg2+ > Na+ > F– > O2– < N3–b)N3– < F– > O2– > Na+ > Mg2+c)Mg2+ < Na+ < F– < O2– < N3–d)N3– > O2– > F– > Na+ < Mg2+Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The correct order of ionic size of N3–, Na+, F–, Mg2+ and O2– is:a)Mg2+ > Na+ > F– > O2– < N3–b)N3– < F– > O2– > Na+ > Mg2+c)Mg2+ < Na+ < F– < O2– < N3–d)N3– > O2– > F– > Na+ < Mg2+Correct answer is option 'C'. Can you explain this answer?.
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