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In the cubic packed structure of mixed oxides, the lattice is made up of oxide ions, 20% of the tetrahedral voids are occupied by divalent X2+ ions and 50% of the octahedral voids are occupied by trivalent Y3+ ions. The formula of the oxide is
- a)X2YO
- b)X4Y5O10
- c)X5Y4O10
- d)XY2O4
Correct answer is option 'B'. Can you explain this answer?
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In the cubic packed structure of mixed oxides, the lattice is made up ...
**Given Information:**
- The cubic packed structure is made up of oxide ions.
- 20% of the tetrahedral voids are occupied by divalent X2 ions.
- 50% of the octahedral voids are occupied by trivalent Y3 ions.
**Analysis:**
The cubic packed structure consists of two types of voids: tetrahedral voids and octahedral voids. In this structure, the oxide ions are arranged in a cubic close-packed (ccp) arrangement, which forms a face-centered cubic (fcc) lattice.
**Determining the Formula:**
To determine the formula of the oxide, we need to consider the ratio of the cations (X2 and Y3) to the anions (oxide ions).
1. Tetrahedral Voids:
- The tetrahedral voids are occupied by divalent X2 ions.
- Given that 20% of the tetrahedral voids are occupied by X2 ions, this means that the ratio of X2 ions to oxide ions in the tetrahedral voids is 1:5. (For every 1 X2 ion, there are 5 oxide ions in the tetrahedral voids)
2. Octahedral Voids:
- The octahedral voids are occupied by trivalent Y3 ions.
- Given that 50% of the octahedral voids are occupied by Y3 ions, this means that the ratio of Y3 ions to oxide ions in the octahedral voids is 1:2. (For every 1 Y3 ion, there are 2 oxide ions in the octahedral voids)
3. Overall Ratio:
- To determine the overall ratio of cations to anions, we need to consider both the tetrahedral and octahedral voids.
- Since the ratio of X2 ions to oxide ions in the tetrahedral voids is 1:5 and the ratio of Y3 ions to oxide ions in the octahedral voids is 1:2, we can combine these ratios to get the overall ratio.
- The overall ratio of X2 ions to oxide ions is (1:5) + (1:2) = (7:10).
**Final Formula:**
The formula of the oxide can be represented as X4Y5O10. This represents the ratio of cations to anions in the cubic packed structure of mixed oxides. Therefore, the correct answer is option B) X4Y5O10.
- The cubic packed structure is made up of oxide ions.
- 20% of the tetrahedral voids are occupied by divalent X2 ions.
- 50% of the octahedral voids are occupied by trivalent Y3 ions.
**Analysis:**
The cubic packed structure consists of two types of voids: tetrahedral voids and octahedral voids. In this structure, the oxide ions are arranged in a cubic close-packed (ccp) arrangement, which forms a face-centered cubic (fcc) lattice.
**Determining the Formula:**
To determine the formula of the oxide, we need to consider the ratio of the cations (X2 and Y3) to the anions (oxide ions).
1. Tetrahedral Voids:
- The tetrahedral voids are occupied by divalent X2 ions.
- Given that 20% of the tetrahedral voids are occupied by X2 ions, this means that the ratio of X2 ions to oxide ions in the tetrahedral voids is 1:5. (For every 1 X2 ion, there are 5 oxide ions in the tetrahedral voids)
2. Octahedral Voids:
- The octahedral voids are occupied by trivalent Y3 ions.
- Given that 50% of the octahedral voids are occupied by Y3 ions, this means that the ratio of Y3 ions to oxide ions in the octahedral voids is 1:2. (For every 1 Y3 ion, there are 2 oxide ions in the octahedral voids)
3. Overall Ratio:
- To determine the overall ratio of cations to anions, we need to consider both the tetrahedral and octahedral voids.
- Since the ratio of X2 ions to oxide ions in the tetrahedral voids is 1:5 and the ratio of Y3 ions to oxide ions in the octahedral voids is 1:2, we can combine these ratios to get the overall ratio.
- The overall ratio of X2 ions to oxide ions is (1:5) + (1:2) = (7:10).
**Final Formula:**
The formula of the oxide can be represented as X4Y5O10. This represents the ratio of cations to anions in the cubic packed structure of mixed oxides. Therefore, the correct answer is option B) X4Y5O10.
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In the cubic packed structure of mixed oxides, the lattice is made up of oxide ions, 20% of the tetrahedral voids are occupied by divalent X2+ ions and 50% of the octahedral voids are occupied by trivalent Y3+ ions. The formula of the oxide isa)X2YOb)X4Y5O10c)X5Y4O10d)XY2O4Correct answer is option 'B'. Can you explain this answer?
Question Description
In the cubic packed structure of mixed oxides, the lattice is made up of oxide ions, 20% of the tetrahedral voids are occupied by divalent X2+ ions and 50% of the octahedral voids are occupied by trivalent Y3+ ions. The formula of the oxide isa)X2YOb)X4Y5O10c)X5Y4O10d)XY2O4Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the cubic packed structure of mixed oxides, the lattice is made up of oxide ions, 20% of the tetrahedral voids are occupied by divalent X2+ ions and 50% of the octahedral voids are occupied by trivalent Y3+ ions. The formula of the oxide isa)X2YOb)X4Y5O10c)X5Y4O10d)XY2O4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the cubic packed structure of mixed oxides, the lattice is made up of oxide ions, 20% of the tetrahedral voids are occupied by divalent X2+ ions and 50% of the octahedral voids are occupied by trivalent Y3+ ions. The formula of the oxide isa)X2YOb)X4Y5O10c)X5Y4O10d)XY2O4Correct answer is option 'B'. Can you explain this answer?.
In the cubic packed structure of mixed oxides, the lattice is made up of oxide ions, 20% of the tetrahedral voids are occupied by divalent X2+ ions and 50% of the octahedral voids are occupied by trivalent Y3+ ions. The formula of the oxide isa)X2YOb)X4Y5O10c)X5Y4O10d)XY2O4Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the cubic packed structure of mixed oxides, the lattice is made up of oxide ions, 20% of the tetrahedral voids are occupied by divalent X2+ ions and 50% of the octahedral voids are occupied by trivalent Y3+ ions. The formula of the oxide isa)X2YOb)X4Y5O10c)X5Y4O10d)XY2O4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the cubic packed structure of mixed oxides, the lattice is made up of oxide ions, 20% of the tetrahedral voids are occupied by divalent X2+ ions and 50% of the octahedral voids are occupied by trivalent Y3+ ions. The formula of the oxide isa)X2YOb)X4Y5O10c)X5Y4O10d)XY2O4Correct answer is option 'B'. Can you explain this answer?.
Solutions for In the cubic packed structure of mixed oxides, the lattice is made up of oxide ions, 20% of the tetrahedral voids are occupied by divalent X2+ ions and 50% of the octahedral voids are occupied by trivalent Y3+ ions. The formula of the oxide isa)X2YOb)X4Y5O10c)X5Y4O10d)XY2O4Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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ample number of questions to practice In the cubic packed structure of mixed oxides, the lattice is made up of oxide ions, 20% of the tetrahedral voids are occupied by divalent X2+ ions and 50% of the octahedral voids are occupied by trivalent Y3+ ions. The formula of the oxide isa)X2YOb)X4Y5O10c)X5Y4O10d)XY2O4Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
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