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A firework is accelerated from rest to a velocity of 50m/s over a distance of 0.250m.calculate the acceleration,how long it take ?
Verified Answer
A firework is accelerated from rest to a velocity of 50m/s over a dist...
V2 = u2 + 2aS
Initial velocity= u = 0.
Final velocity= v = 50 m/s.
Distance= S = 0.250 m
a = 502/(2 x 0.250)
= 5000 m/s2
This question is part of UPSC exam. View all Class 9 courses
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A firework is accelerated from rest to a velocity of 50m/s over a dist...
Acceleration Calculation:
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 50 m/s
- Distance (s) = 0.250 m
Using the equation of motion:
v^2 = u^2 + 2as
(50)^2 = (0)^2 + 2 * a * 0.250
2500 = 0.5a
a = 2500 / 0.5
a = 5000 m/s^2
Therefore, the acceleration of the firework is 5000 m/s^2.
Time Calculation:
- Using the equation of motion:
v = u + at
50 = 0 + 5000 * t
t = 50 / 5000
t = 0.01 s
Therefore, it takes 0.01 seconds for the firework to reach a velocity of 50 m/s over a distance of 0.250m.
Explanation:
The acceleration of the firework is calculated using the equation of motion relating initial velocity, final velocity, acceleration, and distance. Once the acceleration is determined, the time taken for the firework to reach a velocity of 50 m/s is calculated using the same equation of motion. These calculations help understand the motion of the firework and how quickly it accelerates to its final velocity over the given distance.
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 50 m/s
- Distance (s) = 0.250 m
Using the equation of motion:
v^2 = u^2 + 2as
(50)^2 = (0)^2 + 2 * a * 0.250
2500 = 0.5a
a = 2500 / 0.5
a = 5000 m/s^2
Therefore, the acceleration of the firework is 5000 m/s^2.
Time Calculation:
- Using the equation of motion:
v = u + at
50 = 0 + 5000 * t
t = 50 / 5000
t = 0.01 s
Therefore, it takes 0.01 seconds for the firework to reach a velocity of 50 m/s over a distance of 0.250m.
Explanation:
The acceleration of the firework is calculated using the equation of motion relating initial velocity, final velocity, acceleration, and distance. Once the acceleration is determined, the time taken for the firework to reach a velocity of 50 m/s is calculated using the same equation of motion. These calculations help understand the motion of the firework and how quickly it accelerates to its final velocity over the given distance.
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A firework is accelerated from rest to a velocity of 50m/s over a distance of 0.250m.calculate the acceleration,how long it take ?
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A firework is accelerated from rest to a velocity of 50m/s over a distance of 0.250m.calculate the acceleration,how long it take ? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A firework is accelerated from rest to a velocity of 50m/s over a distance of 0.250m.calculate the acceleration,how long it take ? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A firework is accelerated from rest to a velocity of 50m/s over a distance of 0.250m.calculate the acceleration,how long it take ?.
A firework is accelerated from rest to a velocity of 50m/s over a distance of 0.250m.calculate the acceleration,how long it take ? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A firework is accelerated from rest to a velocity of 50m/s over a distance of 0.250m.calculate the acceleration,how long it take ? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A firework is accelerated from rest to a velocity of 50m/s over a distance of 0.250m.calculate the acceleration,how long it take ?.
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