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The breaks apply to a car produce an acceleration of 6m/s in opposite directions to the motions. If the car takes 3 sec come to rest after applying break calculate • initial Velocity •the distance covered by a car before stopping?
Verified Answer
The breaks apply to a car produce an acceleration of 6m/s in opposite ...
Acceleration a = -6 m/s^2
Time t = 2 s
Final velocity v = 0 m/s
Let initial velocity be u
Let distance be s
v = u + at
So, 0 = u + (-6)(2)
So, u = 12 m/s
Now, s = ut + (1/2) at^2
So, s = 12(2) + (1/2)(-6)(2^2)
So, s = 24 - 12
So, s = 12 m
Thus, distance travelled is 12 m
This question is part of UPSC exam. View all Class 9 courses
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The breaks apply to a car produce an acceleration of 6m/s in opposite ...
Understanding the Problem:
The problem states that the brakes of a car produce an acceleration of 6m/s in opposite directions to the motion. The car takes 3 seconds to come to a rest after applying the brakes.
Given Data:
Acceleration due to brakes (a) = 6m/s^2
Time taken to come to rest (t) = 3 sec
Finding Initial Velocity:
To find the initial velocity of the car, we can use the formula:
v = u + at
Where:
v = final velocity (0 m/s, as the car comes to rest)
u = initial velocity
a = acceleration due to brakes (6m/s^2)
t = time taken to come to rest (3 sec)
Substitute the given values into the formula:
0 = u + 6 * 3
0 = u + 18
u = -18 m/s
Therefore, the initial velocity of the car is -18 m/s.
Finding Distance Covered:
To find the distance covered by the car before stopping, we can use the formula:
s = ut + (1/2)at^2
Where:
s = distance covered
u = initial velocity (-18 m/s)
t = time taken to come to rest (3 sec)
a = acceleration due to brakes (6m/s^2)
Substitute the given values into the formula:
s = -18 * 3 + (1/2) * 6 * (3)^2
s = -54 + 27
s = -27 meters
Therefore, the distance covered by the car before stopping is 27 meters.
The problem states that the brakes of a car produce an acceleration of 6m/s in opposite directions to the motion. The car takes 3 seconds to come to a rest after applying the brakes.
Given Data:
Acceleration due to brakes (a) = 6m/s^2
Time taken to come to rest (t) = 3 sec
Finding Initial Velocity:
To find the initial velocity of the car, we can use the formula:
v = u + at
Where:
v = final velocity (0 m/s, as the car comes to rest)
u = initial velocity
a = acceleration due to brakes (6m/s^2)
t = time taken to come to rest (3 sec)
Substitute the given values into the formula:
0 = u + 6 * 3
0 = u + 18
u = -18 m/s
Therefore, the initial velocity of the car is -18 m/s.
Finding Distance Covered:
To find the distance covered by the car before stopping, we can use the formula:
s = ut + (1/2)at^2
Where:
s = distance covered
u = initial velocity (-18 m/s)
t = time taken to come to rest (3 sec)
a = acceleration due to brakes (6m/s^2)
Substitute the given values into the formula:
s = -18 * 3 + (1/2) * 6 * (3)^2
s = -54 + 27
s = -27 meters
Therefore, the distance covered by the car before stopping is 27 meters.
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The breaks apply to a car produce an acceleration of 6m/s in opposite directions to the motions. If the car takes 3 sec come to rest after applying break calculate • initial Velocity •the distance covered by a car before stopping?
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The breaks apply to a car produce an acceleration of 6m/s in opposite directions to the motions. If the car takes 3 sec come to rest after applying break calculate • initial Velocity •the distance covered by a car before stopping? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The breaks apply to a car produce an acceleration of 6m/s in opposite directions to the motions. If the car takes 3 sec come to rest after applying break calculate • initial Velocity •the distance covered by a car before stopping? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The breaks apply to a car produce an acceleration of 6m/s in opposite directions to the motions. If the car takes 3 sec come to rest after applying break calculate • initial Velocity •the distance covered by a car before stopping?.
The breaks apply to a car produce an acceleration of 6m/s in opposite directions to the motions. If the car takes 3 sec come to rest after applying break calculate • initial Velocity •the distance covered by a car before stopping? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The breaks apply to a car produce an acceleration of 6m/s in opposite directions to the motions. If the car takes 3 sec come to rest after applying break calculate • initial Velocity •the distance covered by a car before stopping? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The breaks apply to a car produce an acceleration of 6m/s in opposite directions to the motions. If the car takes 3 sec come to rest after applying break calculate • initial Velocity •the distance covered by a car before stopping?.
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