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Break applied to a car produced an acceleration of 6m/s^2 in opposite direction to motion . If the car takes 2 second to stop after application of breaks.The calculate the distance it travels during this time.?
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Calculation of Distance Traveled During Braking
1. Given Data:
- Acceleration due to braking, a = -6 m/s^2 (opposite direction to motion)
- Time taken to stop, t = 2 seconds
2. Using the equation of motion:
- v = u + at
- where v = final velocity (0 m/s as the car stops), u = initial velocity (unknown), a = acceleration, t = time
3. Calculating initial velocity:
- 0 = u - 6(2)
- u = 12 m/s
4. Using another equation of motion:
- s = ut + 0.5at^2
- where s = distance traveled during braking, u = initial velocity, a = acceleration, t = time
5. Calculating distance traveled:
- s = 12(2) + 0.5(-6)(2)^2
- s = 24 - 6(4)
- s = 24 - 12
- s = 12 meters
Therefore, the car travels a distance of 12 meters during the 2 seconds it takes to stop after the application of brakes.
1. Given Data:
- Acceleration due to braking, a = -6 m/s^2 (opposite direction to motion)
- Time taken to stop, t = 2 seconds
2. Using the equation of motion:
- v = u + at
- where v = final velocity (0 m/s as the car stops), u = initial velocity (unknown), a = acceleration, t = time
3. Calculating initial velocity:
- 0 = u - 6(2)
- u = 12 m/s
4. Using another equation of motion:
- s = ut + 0.5at^2
- where s = distance traveled during braking, u = initial velocity, a = acceleration, t = time
5. Calculating distance traveled:
- s = 12(2) + 0.5(-6)(2)^2
- s = 24 - 6(4)
- s = 24 - 12
- s = 12 meters
Therefore, the car travels a distance of 12 meters during the 2 seconds it takes to stop after the application of brakes.
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Break applied to a car produced an acceleration of 6m/s^2 in opposite direction to motion . If the car takes 2 second to stop after application of breaks.The calculate the distance it travels during this time.?
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Break applied to a car produced an acceleration of 6m/s^2 in opposite direction to motion . If the car takes 2 second to stop after application of breaks.The calculate the distance it travels during this time.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Break applied to a car produced an acceleration of 6m/s^2 in opposite direction to motion . If the car takes 2 second to stop after application of breaks.The calculate the distance it travels during this time.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Break applied to a car produced an acceleration of 6m/s^2 in opposite direction to motion . If the car takes 2 second to stop after application of breaks.The calculate the distance it travels during this time.?.
Break applied to a car produced an acceleration of 6m/s^2 in opposite direction to motion . If the car takes 2 second to stop after application of breaks.The calculate the distance it travels during this time.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Break applied to a car produced an acceleration of 6m/s^2 in opposite direction to motion . If the car takes 2 second to stop after application of breaks.The calculate the distance it travels during this time.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Break applied to a car produced an acceleration of 6m/s^2 in opposite direction to motion . If the car takes 2 second to stop after application of breaks.The calculate the distance it travels during this time.?.
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