A current I flows through a uniform wire of diameter d when the mean e...
Brother, I may be wrong but I think the correct answer is (d). As:
i=n�a�e�v and I=n�e�A�V.
But we have i=I, then
neav= neAV
>av=AV but, a=π(d/2)square
>a=π(d sq./4). Similarly we have A=π (d sq./16)
Now putting the value of a and A in the eqn we get
>π(d sq./4)/π(d sq./16)=V/v
>4v=V
Hence,the new velocity is 4v.
A current I flows through a uniform wire of diameter d when the mean e...
Explanation:
Formula: Current density J = nqVdA
Where,
n = Number density of electrons
q = Charge on an electron
Vd = Drift velocity of electrons
A = Area of cross-section of the wire
1. Let's assume the current flowing through the wire of diameter d is I.
2. The current density J is given by J = I / (πd²/4)
3. Using the formula for current density, we can write J = nqVdA
4. As the material of both wires is the same, the number density of electrons will also be the same. Hence, n is constant.
5. Since the current is the same in both wires, we can equate the current densities:
J₁ = J₂
I / (πd²/4) = I / (π(d/2)²/4)
6. Simplifying the above equation, we get:
d² = (d/2)² * 4
d² = d²
1 = 4
This is not possible, so there must be an error in our assumption.
7. Let's assume that the mean electron drift velocity in the wire of diameter d/2 is V₂.
8. Using the formula for current density, we can write J = nqVdA = nqV₂(d/2)²π/4
9. Since the current is the same as in the wire of diameter d, we can equate the current densities:
J₁ = J₂
I / (πd²/4) = nqV₂(d/2)²π/4
10. Simplifying the above equation, we get:
V₂ = 2V
11. Therefore, the mean electron drift velocity in the wire of diameter d/2 is 2V.
12. The same current will flow through a wire of diameter d/2 made of the same material if the mean drift velocity of the electron is 2V. Hence, the correct answer is option C (2V).