CA Foundation Exam > CA Foundation Questions > Log a+b/3=1/2(log a+log b) then the value of ...
Start Learning for Free
Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ?
Most Upvoted Answer
Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ?
Solution:
Given, log a b/3 = 1/2(log a log b)
We can write this as:
log a b − log a 3 = 1/2(log a + log b)
Using the properties of logarithms, we can simplify this expression:
log a (b/3) = 1/2(log a b) + 1/2(log a 3)
log a (b/3) = 1/2(log a b) + 1/2(1)
log a (b/3) = 1/2(log a b) + 1/2
Now, let's solve for log a b:
2log a (b/3) = log a b + 1
2log a b − 2log a 3 = log a b + 1
2log a b − log a 9 = log a b + 1
log a b = 3 − 1 = 2
Now we can find the value of a/b and b/a:
a/b = antilog(log a b − log a a) = antilog(2 − 1) = antilog(1) = 10
b/a = antilog(log a a − log a b) = antilog(0 − 2) = antilog(-2) = 0.01
Answer:
a/b = 10
b/a = 0.01
Given, log a b/3 = 1/2(log a log b)
We can write this as:
log a b − log a 3 = 1/2(log a + log b)
Using the properties of logarithms, we can simplify this expression:
log a (b/3) = 1/2(log a b) + 1/2(log a 3)
log a (b/3) = 1/2(log a b) + 1/2(1)
log a (b/3) = 1/2(log a b) + 1/2
Now, let's solve for log a b:
2log a (b/3) = log a b + 1
2log a b − 2log a 3 = log a b + 1
2log a b − log a 9 = log a b + 1
log a b = 3 − 1 = 2
Now we can find the value of a/b and b/a:
a/b = antilog(log a b − log a a) = antilog(2 − 1) = antilog(1) = 10
b/a = antilog(log a a − log a b) = antilog(0 − 2) = antilog(-2) = 0.01
Answer:
a/b = 10
b/a = 0.01
Community Answer
Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ?
Log {(a+b) /3} =1/2(loga +logb)
log{(a+b) /3} = 1/2(logab)
log{(a+b)/3} = (logab) ½
(a+b) /3 = (ab)½
squaring on both sides
(a²+b²+2ab) /9 = ab
a²+b²+2ab = 9ab
a²+b² = 7ab
divide "ab" on both sides
a/b + b/a =7
log{(a+b) /3} = 1/2(logab)
log{(a+b)/3} = (logab) ½
(a+b) /3 = (ab)½
squaring on both sides
(a²+b²+2ab) /9 = ab
a²+b²+2ab = 9ab
a²+b² = 7ab
divide "ab" on both sides
a/b + b/a =7
Attention CA Foundation Students!
To make sure you are not studying endlessly, EduRev has designed CA Foundation study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CA Foundation.
|
Explore Courses for CA Foundation exam
|
|
Similar CA Foundation Doubts
Top Courses for CA FoundationView all
Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ?
Question Description
Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ?.
Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ?.
Solutions for Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ? in English & in Hindi are available as part of our courses for CA Foundation.
Download more important topics, notes, lectures and mock test series for CA Foundation Exam by signing up for free.
Here you can find the meaning of Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ? defined & explained in the simplest way possible. Besides giving the explanation of
Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ?, a detailed solution for Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ? has been provided alongside types of Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ? theory, EduRev gives you an
ample number of questions to practice Log a+b/3=1/2(log a+log b) then the value of a/b+b/a is ? tests, examples and also practice CA Foundation tests.
|
|
Explore Courses for CA Foundation exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup