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Which Geometric shapes encloses more area: a square of side 2 cm ; a rectangle of side 3 cm and 2 cm ; An equilateral triangle of side 4 cm?
- a)Equilateral triangle
- b)square
- c)Rectangle
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Which Geometric shapes encloses more area: a square of side 2 cm ; a r...
Area of a square = a2 = (2 x 2) cm2
= 4 cm2
= 4 cm2
Area of rectangle = L X B
= (3 x 2 ) cm2
= 6 cm2
= (3 x 2 ) cm2
= 6 cm2
Area of an equilateral triangle = root 3/4 .a2
= root 3/4 × (4)2
= 1.732 / 4 × 16
= 0.433 × 16
= 6.928 cm2
= root 3/4 × (4)2
= 1.732 / 4 × 16
= 0.433 × 16
= 6.928 cm2
Since the area of an equilateral triangle is more than area of a square and rectangle. So equilateral triangle encloses more area
So option A is the correct answer.
This question is part of UPSC exam. View all Class 7 courses
Most Upvoted Answer
Which Geometric shapes encloses more area: a square of side 2 cm ; a r...
Area of sq =s multiply s
2×2=4
area of rec = 3×2=6
area of triangle = 1/2×b×h
1/2×4×4
8
2×2=4
area of rec = 3×2=6
area of triangle = 1/2×b×h
1/2×4×4
8
Community Answer
Which Geometric shapes encloses more area: a square of side 2 cm ; a r...
Explanation:
To find out which figure encloses more area, we need to calculate the area of each figure and compare them.
Area of a Square:
Given side of the square is 2 cm,
Area of the square = side x side = 2 cm x 2 cm = 4 sq.cm
Area of a Rectangle:
Given length of the rectangle is 3 cm and breadth is 2 cm,
Area of the rectangle = length x breadth = 3 cm x 2 cm = 6 sq.cm
Area of an Equilateral Triangle:
Given side of the equilateral triangle is 4 cm,
Area of the equilateral triangle = (√3 / 4) x side^2 = (√3 / 4) x 4 cm x 4 cm = 4√3 sq.cm
Comparing the Areas:
From the above calculations, we can see that the area of the equilateral triangle is greater than the area of the square and the rectangle. Therefore, the correct option is (a) equilateral triangle.
Hence, an equilateral triangle of side 4 cm encloses more area than a square of side 2 cm and a rectangle of side 3 cm and 2 cm.
To find out which figure encloses more area, we need to calculate the area of each figure and compare them.
Area of a Square:
Given side of the square is 2 cm,
Area of the square = side x side = 2 cm x 2 cm = 4 sq.cm
Area of a Rectangle:
Given length of the rectangle is 3 cm and breadth is 2 cm,
Area of the rectangle = length x breadth = 3 cm x 2 cm = 6 sq.cm
Area of an Equilateral Triangle:
Given side of the equilateral triangle is 4 cm,
Area of the equilateral triangle = (√3 / 4) x side^2 = (√3 / 4) x 4 cm x 4 cm = 4√3 sq.cm
Comparing the Areas:
From the above calculations, we can see that the area of the equilateral triangle is greater than the area of the square and the rectangle. Therefore, the correct option is (a) equilateral triangle.
Hence, an equilateral triangle of side 4 cm encloses more area than a square of side 2 cm and a rectangle of side 3 cm and 2 cm.
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Which Geometric shapes encloses more area: a square of side 2 cm ; a rectangle of side 3 cm and 2 cm ; An equilateral triangle of side 4 cm?a)Equilateraltriangleb)squarec)Rectangled)None of theseCorrect answer is option 'A'. Can you explain this answer?
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