CA Foundation Exam > CA Foundation Questions > Find the equation of the line joining the poi...
Start Learning for Free
Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.
- a)6x+y+23=0
- b)6x+y-23=0
- c)6x+2y+14=0
- d)2x+5y+5=0
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Find the equation of the line joining the point (3, 5) with the point ...
To find the equation of the line joining the point (3, 5) with the point of intersection of 2x + 3y - 5 = 0 and 3x + 5y - 7 = 0, we need to follow the steps given below:
Step 1: Find the point of intersection of the two lines 2x + 3y - 5 = 0 and 3x + 5y - 7 = 0.
Multiplying the first equation by 5 and the second equation by 3, we get:
10x + 15y - 25 = 0
9x + 15y - 21 = 0
Subtracting the second equation from the first, we get:
x = 4
Substituting x = 4 in either of the two equations, we get:
y = -1
Therefore, the point of intersection is (4, -1).
Step 2: Find the slope of the line joining the two points (3, 5) and (4, -1).
Using the formula for slope, we get:
slope = (y2 - y1)/(x2 - x1)
= (-1 - 5)/(4 - 3)
= -6
Step 3: Use the point-slope form of the equation of a line to find the equation of the line passing through the point (3, 5) with slope -6.
Using the point-slope form, we get:
y - 5 = -6(x - 3)
Simplifying and rearranging, we get:
y = -6x + 23
Therefore, the equation of the line joining the point (3, 5) with the point of intersection of 2x + 3y - 5 = 0 and 3x + 5y - 7 = 0 is 6x - y - 23 = 0, which is option B.
Step 1: Find the point of intersection of the two lines 2x + 3y - 5 = 0 and 3x + 5y - 7 = 0.
Multiplying the first equation by 5 and the second equation by 3, we get:
10x + 15y - 25 = 0
9x + 15y - 21 = 0
Subtracting the second equation from the first, we get:
x = 4
Substituting x = 4 in either of the two equations, we get:
y = -1
Therefore, the point of intersection is (4, -1).
Step 2: Find the slope of the line joining the two points (3, 5) and (4, -1).
Using the formula for slope, we get:
slope = (y2 - y1)/(x2 - x1)
= (-1 - 5)/(4 - 3)
= -6
Step 3: Use the point-slope form of the equation of a line to find the equation of the line passing through the point (3, 5) with slope -6.
Using the point-slope form, we get:
y - 5 = -6(x - 3)
Simplifying and rearranging, we get:
y = -6x + 23
Therefore, the equation of the line joining the point (3, 5) with the point of intersection of 2x + 3y - 5 = 0 and 3x + 5y - 7 = 0 is 6x - y - 23 = 0, which is option B.
Free Test
FREE
| Start Free Test |
Community Answer
Find the equation of the line joining the point (3, 5) with the point ...
Substitute (3,5) in the given 4 options . it will satisfy any one.
Attention CA Foundation Students!
To make sure you are not studying endlessly, EduRev has designed CA Foundation study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CA Foundation.
|
Explore Courses for CA Foundation exam
|
|
Top Courses for CA FoundationView all
Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer?
Question Description
Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer?.
Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer?.
Solutions for Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for CA Foundation.
Download more important topics, notes, lectures and mock test series for CA Foundation Exam by signing up for free.
Here you can find the meaning of Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Find the equation of the line joining the point (3, 5) with the point of intersection 2x+3y-5=0 and 3x+5y-7=0.a)6x+y+23=0b)6x+y-23=0c)6x+2y+14=0d)2x+5y+5=0Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice CA Foundation tests.
|
|
Explore Courses for CA Foundation exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup