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A radioactive element undergoes 80% radioactive decay in 300 min. The half- life for this species in minutes is _________.
    Correct answer is '129.15'. Can you explain this answer?
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    Explanation:


    • Radioactive decay is a process by which the nucleus of an unstable atom loses energy by emitting particles or electromagnetic radiation.

    • The rate of radioactive decay is measured by the half-life of the radioactive element.

    • Half-life is the time taken for half of the radioactive atoms to decay.

    • The formula for half-life is given by:


    t1/2 = (ln 2)/λ


    • Where t1/2 is the half-life, λ is the decay constant, and ln is the natural logarithm.

    • To find the half-life of the given radioactive element, we need to know the decay constant.

    • The decay constant can be calculated using the formula:


    λ = (ln N0/Nt)/t


    • Where N0 is the initial number of radioactive atoms, Nt is the number of radioactive atoms at time t, and t is the time taken for decay.

    • In this case, it is given that the radioactive element undergoes 80% decay in 300 min.

    • This means that Nt = 0.2N0 (since 80% of the atoms have decayed).

    • Substituting these values in the above formula, we get:


    λ = (ln 5)/(300 min)


    • Now we can use this value of λ to calculate the half-life using the formula:


    t1/2 = (ln 2)/λ


    • Substituting the value of λ, we get:


    t1/2 = (ln 2)/(ln 5/300 min) = 129.15 min


    • Therefore, the half-life of the given radioactive element is 129.15 minutes.

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