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Two semiconductor material have exactly the same properties except that material A has a bandgap of 1.0eV and material B has a bandgap energy of 1.2 eV. The ratio of intrinsic concentration of material A to that of material B is
  • a)
    2016
  • b)
    47.5
  • c)
    58.23
  • d)
    1048
Correct answer is option 'B'. Can you explain this answer?
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Explanation:

Intrinsic concentration is the concentration of electrons and holes in a semiconductor when it is in thermal equilibrium at a certain temperature. It is denoted by 'ni' and depends on the bandgap energy of the semiconductor material.

The ratio of intrinsic concentration of material A to that of material B can be calculated as follows:

niA/niB = exp[(EgB - EgA)/(2kT)]

where EgA and EgB are the bandgap energies of materials A and B respectively, k is Boltzmann's constant, and T is the temperature in Kelvin.

Given that EgA = 1.0 eV and EgB = 1.2 eV, we can substitute these values in the above equation and simplify to get:

niA/niB = exp[(1.2 - 1.0)/(2kT)] = exp[0.1/(2kT)]

We can further simplify this expression by assuming room temperature (T = 300 K) and substituting the value of Boltzmann's constant (k = 8.62e-5 eV/K) to get:

niA/niB = exp(0.1/(2*8.62e-5*300)) = 47.5

Therefore, the ratio of intrinsic concentration of material A to that of material B is 47.5.

Hence, option 'B' is the correct answer.
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