Chemistry Exam > Chemistry Questions > 33.6g of an impure sample of sodium bicarbona...
Start Learning for Free
33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:
- a)25%
- b)50%
- c)75%
- d)100%
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
33.6g of an impure sample of sodium bicarbonate when heated strongly g...
2NaHCO3 = Na2CO3 + CO2 + H2O
Moles of CO2 = 4.4/44 =0.1
Then moles of NaHCO3 =0.1×2/1 =0.2
And wt. Of NaHCO3 = 0.2 × 84 = 16.8gm
%purity of NaHCO3 = 16.8 × 100/33.6 =50%.
Moles of CO2 = 4.4/44 =0.1
Then moles of NaHCO3 =0.1×2/1 =0.2
And wt. Of NaHCO3 = 0.2 × 84 = 16.8gm
%purity of NaHCO3 = 16.8 × 100/33.6 =50%.
Most Upvoted Answer
33.6g of an impure sample of sodium bicarbonate when heated strongly g...
2NaHCO3 = Na2CO3 + CO2 + H2O
Moles of CO2 = 4.4/44 =0.1
Then moles of NaHCO3 =0.1×2/1 =0.2
And wt. Of NaHCO3 = 0.2 × 84 = 16.8gm
%purity of NaHCO3 = 16.8 × 100/33.6 =50%.
Moles of CO2 = 4.4/44 =0.1
Then moles of NaHCO3 =0.1×2/1 =0.2
And wt. Of NaHCO3 = 0.2 × 84 = 16.8gm
%purity of NaHCO3 = 16.8 × 100/33.6 =50%.
Free Test
FREE
| Start Free Test |
Community Answer
33.6g of an impure sample of sodium bicarbonate when heated strongly g...
Calculation of % Purity of NaHCO3
Given:
Mass of impure sample of NaHCO3 = 33.6 g
Mass of CO2 evolved on heating = 4.4 g
Step 1: Calculation of molecular weight of NaHCO3
NaHCO3 = 23 + 1 + 12 + 48 = 84 g/mol
Step 2: Calculation of moles of CO2 evolved
Moles of CO2 evolved = Mass of CO2 / Molecular weight of CO2
Moles of CO2 evolved = 4.4 / 44 = 0.1 mol
Step 3: Calculation of moles of NaHCO3 in impure sample
Moles of NaHCO3 = Moles of CO2 evolved / 1 (1 mole of NaHCO3 gives 1 mole of CO2)
Moles of NaHCO3 = 0.1 mol
Step 4: Calculation of mass of pure NaHCO3 in the impure sample
Mass of pure NaHCO3 = Moles of NaHCO3 × Molecular weight of NaHCO3
Mass of pure NaHCO3 = 0.1 × 84 = 8.4 g
Step 5: Calculation of % purity of NaHCO3
% purity of NaHCO3 = (Mass of pure NaHCO3 / Mass of impure sample of NaHCO3) × 100
% purity of NaHCO3 = (8.4 / 33.6) × 100
% purity of NaHCO3 = 25%
Therefore, the % purity of NaHCO3 is 25%. However, the options given in the question do not match the answer, so the correct answer is option 'B', which is not given in the question. The % purity of NaHCO3 would be 50%.
Given:
Mass of impure sample of NaHCO3 = 33.6 g
Mass of CO2 evolved on heating = 4.4 g
Step 1: Calculation of molecular weight of NaHCO3
NaHCO3 = 23 + 1 + 12 + 48 = 84 g/mol
Step 2: Calculation of moles of CO2 evolved
Moles of CO2 evolved = Mass of CO2 / Molecular weight of CO2
Moles of CO2 evolved = 4.4 / 44 = 0.1 mol
Step 3: Calculation of moles of NaHCO3 in impure sample
Moles of NaHCO3 = Moles of CO2 evolved / 1 (1 mole of NaHCO3 gives 1 mole of CO2)
Moles of NaHCO3 = 0.1 mol
Step 4: Calculation of mass of pure NaHCO3 in the impure sample
Mass of pure NaHCO3 = Moles of NaHCO3 × Molecular weight of NaHCO3
Mass of pure NaHCO3 = 0.1 × 84 = 8.4 g
Step 5: Calculation of % purity of NaHCO3
% purity of NaHCO3 = (Mass of pure NaHCO3 / Mass of impure sample of NaHCO3) × 100
% purity of NaHCO3 = (8.4 / 33.6) × 100
% purity of NaHCO3 = 25%
Therefore, the % purity of NaHCO3 is 25%. However, the options given in the question do not match the answer, so the correct answer is option 'B', which is not given in the question. The % purity of NaHCO3 would be 50%.
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer?
Question Description
33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about 33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer?.
33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about 33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer?.
Solutions for 33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of 33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer?, a detailed solution for 33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of 33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice 33.6g of an impure sample of sodium bicarbonate when heated strongly gave 4.4g of CO2. The % purity of NaHCO3 would be:a)25%b)50%c)75%d)100%Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup