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In the reaction of sodium thiosulphate with I2 in aqueous medium the equivalent weight of sodium thiosulphate is equal to:
- a)Molar mass of sodium thiosulphate
- b)The average of molar masses of Na2S2O3 and I2
- c)Half the molar mass of sodium thiosulphate
- d)Molar mass of I2 x2
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
In the reaction of sodium thiosulphate with I2 in aqueous medium the e...
The equivalent weight is the gram molecular weight divided by the number of electrons lost or gained by each molecule; For sodium thiosulfate (Na2S2O3.5H2O), this is (248.17/1) g.
In case of Sodium Thiosulfate the reation proceeds as under:
I2 + 2 Na2S2O3 → Na2S4O6 + 2 NaI
2 Na2S2O3 ≡ I2 ≡ 2 e
Hence for one Na2S2O3 ≡ 1 e
Thus Molecular weight divided by 1 is the equivalent weight & hence both have same value.
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In the reaction of sodium thiosulphate with I2 in aqueous medium the e...
Solution:
The reaction of sodium thiosulphate (Na2S2O3) with iodine (I2) in aqueous medium can be represented as follows:
2Na2S2O3 + I2 → Na2S4O6 + 2NaI
In this reaction, 2 moles of sodium thiosulphate react with 1 mole of iodine to form 1 mole of sodium tetrathionate and 2 moles of sodium iodide.
Now, let's calculate the equivalent weight of sodium thiosulphate.
Definition of equivalent weight:
The equivalent weight of a substance is the ratio of its molar mass to the number of equivalents produced or consumed in a reaction.
Molar mass of sodium thiosulphate (Na2S2O3):
The molar mass of Na2S2O3 can be calculated as follows:
Molar mass of Na = 22.99 g/mol
Molar mass of S = 32.06 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of Na2S2O3 = (2 * 22.99) + (2 * 32.06) + (3 * 16.00) = 158.11 g/mol
Number of equivalents of sodium thiosulphate:
From the balanced chemical equation, we can see that 2 moles of sodium thiosulphate react with 1 mole of iodine. Therefore, 1 mole of sodium thiosulphate is equivalent to half a mole of iodine.
Calculation of equivalent weight:
Equivalent weight = Molar mass / Number of equivalents
For sodium thiosulphate, the equivalent weight can be calculated as:
Equivalent weight = 158.11 g/mol / (1/2) = 316.22 g/mol
Conclusion:
The equivalent weight of sodium thiosulphate is equal to the molar mass of sodium thiosulphate, which is option 'A'.
The reaction of sodium thiosulphate (Na2S2O3) with iodine (I2) in aqueous medium can be represented as follows:
2Na2S2O3 + I2 → Na2S4O6 + 2NaI
In this reaction, 2 moles of sodium thiosulphate react with 1 mole of iodine to form 1 mole of sodium tetrathionate and 2 moles of sodium iodide.
Now, let's calculate the equivalent weight of sodium thiosulphate.
Definition of equivalent weight:
The equivalent weight of a substance is the ratio of its molar mass to the number of equivalents produced or consumed in a reaction.
Molar mass of sodium thiosulphate (Na2S2O3):
The molar mass of Na2S2O3 can be calculated as follows:
Molar mass of Na = 22.99 g/mol
Molar mass of S = 32.06 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of Na2S2O3 = (2 * 22.99) + (2 * 32.06) + (3 * 16.00) = 158.11 g/mol
Number of equivalents of sodium thiosulphate:
From the balanced chemical equation, we can see that 2 moles of sodium thiosulphate react with 1 mole of iodine. Therefore, 1 mole of sodium thiosulphate is equivalent to half a mole of iodine.
Calculation of equivalent weight:
Equivalent weight = Molar mass / Number of equivalents
For sodium thiosulphate, the equivalent weight can be calculated as:
Equivalent weight = 158.11 g/mol / (1/2) = 316.22 g/mol
Conclusion:
The equivalent weight of sodium thiosulphate is equal to the molar mass of sodium thiosulphate, which is option 'A'.
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In the reaction of sodium thiosulphate with I2 in aqueous medium the equivalent weight of sodium thiosulphate is equal to:a)Molar mass of sodium thiosulphateb)The average of molar masses of Na2S2O3 and I2c)Half the molar mass of sodium thiosulphated)Molar mass of I2 x2Correct answer is option 'A'. Can you explain this answer?
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