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The crystal field stabilization energy (CFSE), will be the highest for:
- a)[CoF6]3-
- b)[Co(CNS)4]2-
- c)[Mn(H2O)6]2+
- d)[Co(NH3)6]3+
Correct answer is option 'D'. Can you explain this answer?
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The crystal field stabilization energy (CFSE), will be the highest for...
The crystal field stabilization energy (CFSE) is the stability that results from placing a transition metal ion in the crystal field generated by a set of ligands. Conversely, the eg orbitals (in the octahedral case) are higher in energy than in the barycenter, so putting electrons in these reduces the amount of CFSE.
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The crystal field stabilization energy (CFSE), will be the highest for...
Explanation:
Crystal field stabilization energy (CFSE) is the energy required to place a metal ion in a ligand field. The magnitude of CFSE depends on the geometry of the complex, the oxidation state of the metal ion, and the nature of the ligands.
In the given options, the complex with the highest CFSE is [Co(NH3)6]3+.
Reasons:
1. Geometry: The complex [Co(NH3)6]3+ has an octahedral geometry. Octahedral geometry results in the maximum splitting of d-orbitals, which leads to the highest CFSE.
2. Oxidation State: The oxidation state of cobalt in [Co(NH3)6]3+ is +3. The CFSE increases with the increase in oxidation state of the metal ion.
3. Nature of ligands: Ammonia (NH3) is a weak field ligand. Weak field ligands produce a small splitting of d-orbitals, which results in a high CFSE.
Hence, [Co(NH3)6]3+ has the highest CFSE among the given options.
Note: The CFSE for [CoF6]3- would be lower than [Co(NH3)6]3+ as fluoride is a strong field ligand. The CFSE for [Co(CNS)4]2- and [Mn(H2O)6]2+ would be lower than [Co(NH3)6]3+ as they have lower oxidation states and/or stronger field ligands.
Crystal field stabilization energy (CFSE) is the energy required to place a metal ion in a ligand field. The magnitude of CFSE depends on the geometry of the complex, the oxidation state of the metal ion, and the nature of the ligands.
In the given options, the complex with the highest CFSE is [Co(NH3)6]3+.
Reasons:
1. Geometry: The complex [Co(NH3)6]3+ has an octahedral geometry. Octahedral geometry results in the maximum splitting of d-orbitals, which leads to the highest CFSE.
2. Oxidation State: The oxidation state of cobalt in [Co(NH3)6]3+ is +3. The CFSE increases with the increase in oxidation state of the metal ion.
3. Nature of ligands: Ammonia (NH3) is a weak field ligand. Weak field ligands produce a small splitting of d-orbitals, which results in a high CFSE.
Hence, [Co(NH3)6]3+ has the highest CFSE among the given options.
Note: The CFSE for [CoF6]3- would be lower than [Co(NH3)6]3+ as fluoride is a strong field ligand. The CFSE for [Co(CNS)4]2- and [Mn(H2O)6]2+ would be lower than [Co(NH3)6]3+ as they have lower oxidation states and/or stronger field ligands.
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The crystal field stabilization energy (CFSE), will be the highest for:a)[CoF6]3-b)[Co(CNS)4]2-c)[Mn(H2O)6]2+d)[Co(NH3)6]3+Correct answer is option 'D'. Can you explain this answer?
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