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The crystal field stabilization energy (CFSE) is the highest for:
- a)[CoF4]2–
- b)[Co(NCS)4]2–
- c)[Co(NH3)6]3+
- d)[CoCl4]2–
Correct answer is option 'C'. Can you explain this answer?
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The crystal field stabilization energy (CFSE) is the highest for:a)[Co...
Higher the oxidation state of the metal, greater the crystal field splitting energy . In options (a), (b) and (d), Co is present in +2 oxidation state and in (c ) it is present in +3 oxidation state and hence has a higher value of CFSE.
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The crystal field stabilization energy (CFSE) is the highest for:a)[Co...
The crystal field stabilization energy (CFSE) is determined by the number and arrangement of ligands around the central metal ion. In general, the CFSE is higher for complexes with ligands that cause a larger splitting of the d-orbitals.
In the case of [CoF4]2-, the cobalt ion is surrounded by four fluoride ligands. Fluoride ions are small and highly electronegative, causing a strong ligand field and a significant splitting of the d-orbitals. This leads to a high CFSE for [CoF4]2-.
Therefore, the highest CFSE would be for a) [CoF4]2-.
In the case of [CoF4]2-, the cobalt ion is surrounded by four fluoride ligands. Fluoride ions are small and highly electronegative, causing a strong ligand field and a significant splitting of the d-orbitals. This leads to a high CFSE for [CoF4]2-.
Therefore, the highest CFSE would be for a) [CoF4]2-.
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