Can anyone please answer this question Mohit travels 12km towards nort...
Given Information:
- Mohit travels 12km towards north.
- He then travels some distance towards east.
- Finally, he reaches a position 15km away from his initial position.
To Find:
The distance traveled by Mohit towards the east.
Approach:
Let's assume the distance traveled towards the east is 'x' km.
Analysis:
Movement towards North:
Mohit travels 12km towards the north. This can be represented as:
North: 12km
Movement towards East:
Mohit then travels some distance towards the east. This can be represented as:
East: x km
Final Position:
Finally, Mohit reaches a position 15km away from his initial position. We can represent this as the resultant of the north and east movements using the Pythagorean theorem.
Let's consider the initial position as the origin (0,0) on a coordinate plane.
The final position can be represented as (x, 12).
Using the Pythagorean theorem, we can calculate the distance between the initial and final positions as follows:
Distance = sqrt(x^2 + 12^2)
According to the given information, the distance is 15km. So we have the equation:
15 = sqrt(x^2 + 12^2)
Squaring both sides of the equation, we get:
225 = x^2 + 12^2
225 = x^2 + 144
Rearranging the equation, we have:
x^2 = 225 - 144
x^2 = 81
Taking the square root of both sides, we get:
x = 9
Final Answer:
The distance traveled by Mohit towards the east is 9km.
Can anyone please answer this question Mohit travels 12km towards nort...
Let the distance travelled to east is X according to question 12^2+X^2=15^2 144+X^2=225 X^2=225-144 X^2=81 X=√81 X=9 Metre
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