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One of the electrons of the highest energy level is taken to next excited state in the following diatomic species. Select the species which undergoes change in bond order?
- a)H2
- b)Li2
- c)B2
- d)C2
Correct answer is option 'A,B'. Can you explain this answer?
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Explanation:
The bond order of a diatomic molecule is given by the formula:
Bond Order = (Number of bonding electrons - Number of antibonding electrons) / 2
When an electron is excited to a higher energy level, it moves from a lower energy orbital to a higher energy orbital. This results in a change in the distribution of electrons and can potentially change the bond order of the molecule.
Let's analyze each option:
a) H2:
In the ground state, H2 has a bond order of 1. When an electron is excited to a higher energy level, it creates an antibonding orbital. This leads to a change in the bond order.
b) Li2:
In the ground state, Li2 has a bond order of 1. When an electron is excited to a higher energy level, it creates an antibonding orbital. This leads to a change in the bond order.
c) B2:
In the ground state, B2 has a bond order of 2. The highest energy level of B2 already has all its orbitals filled. Exciting an electron to a higher energy level would not change the distribution of electrons and therefore would not change the bond order.
d) C2:
In the ground state, C2 has a bond order of 3. The highest energy level of C2 already has all its orbitals filled. Exciting an electron to a higher energy level would not change the distribution of electrons and therefore would not change the bond order.
Therefore, the species that undergoes a change in bond order when one of the electrons of the highest energy level is taken to the next excited state is H2 and Li2.
The bond order of a diatomic molecule is given by the formula:
Bond Order = (Number of bonding electrons - Number of antibonding electrons) / 2
When an electron is excited to a higher energy level, it moves from a lower energy orbital to a higher energy orbital. This results in a change in the distribution of electrons and can potentially change the bond order of the molecule.
Let's analyze each option:
a) H2:
In the ground state, H2 has a bond order of 1. When an electron is excited to a higher energy level, it creates an antibonding orbital. This leads to a change in the bond order.
b) Li2:
In the ground state, Li2 has a bond order of 1. When an electron is excited to a higher energy level, it creates an antibonding orbital. This leads to a change in the bond order.
c) B2:
In the ground state, B2 has a bond order of 2. The highest energy level of B2 already has all its orbitals filled. Exciting an electron to a higher energy level would not change the distribution of electrons and therefore would not change the bond order.
d) C2:
In the ground state, C2 has a bond order of 3. The highest energy level of C2 already has all its orbitals filled. Exciting an electron to a higher energy level would not change the distribution of electrons and therefore would not change the bond order.
Therefore, the species that undergoes a change in bond order when one of the electrons of the highest energy level is taken to the next excited state is H2 and Li2.
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One of the electrons of the highest energy level is taken to next excited state in the following diatomic species. Select the species which undergoes change in bond order?a)H2 b)Li2c)B2d)C2Correct answer is option 'A,B'. Can you explain this answer?
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