Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at ra...
To solve this problem, we need to find the probability of drawing a ticket with a number that is a multiple of 3 or 5 out of a set of 20 tickets.
Let's first determine the total number of favorable outcomes, i.e. the number of tickets that are multiples of 3 or 5.
Multiples of 3:
There are 6 multiples of 3 between 1 and 20, which are 3, 6, 9, 12, 15, and 18.
Multiples of 5:
There are 4 multiples of 5 between 1 and 20, which are 5, 10, 15, and 20.
However, we need to be careful not to count the number 15 twice since it is a multiple of both 3 and 5. So, we only count it once.
Therefore, the total number of favorable outcomes is 6 + 4 - 1 = 9.
Next, we determine the total number of possible outcomes, which is simply the number of tickets in the set, which is 20.
Now, we can calculate the probability of drawing a ticket with a number that is a multiple of 3 or 5 by dividing the number of favorable outcomes by the number of possible outcomes:
Probability = Number of favorable outcomes / Number of possible outcomes = 9 / 20
Simplifying this fraction, we find that the probability is 9/20.
Therefore, the correct answer is option D) 9/20.
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at ra...
Sample space is 20 and p(E) is 9 because multiples with 3 is. 6 and with 5 is 4 and there was common no between them 15 so p(E) was 9
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.