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A bucket contains water filled upto a height = 15 cm. The bucket is tied to a rope which is passed over a frictionless light pulley and the other end of the rope is tied to a weight of mass which is half of that of the (bucket + water). The water pressure above atmosphere pressure at the bottom is :
- a)0.5 kPa
- b)1 kPa
- c)5 kPa
- d)None
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A bucket contains water filled upto a height = 15 cm. The bucket is ti...
**Explanation:**
To find the water pressure above atmospheric pressure at the bottom of the bucket, we need to consider the forces acting on the system.
**1. Weight of the bucket and water:**
The weight of the bucket and water can be calculated using the formula:
Weight = mass * acceleration due to gravity
Since the mass of the bucket and water is not given, let's assume it to be 'm'. Therefore, the weight of the bucket and water will be 'm * g', where 'g' is the acceleration due to gravity.
**2. Weight of the hanging weight:**
The weight of the hanging weight can be calculated using the formula:
Weight = mass * acceleration due to gravity
Since the mass of the hanging weight is half of that of the bucket and water, it will be '0.5m * g'.
**3. Tension in the rope:**
The tension in the rope can be calculated by equating the forces acting on the system. Since the bucket and water are in equilibrium, the tension in the rope will be equal to the weight of the bucket and water plus the weight of the hanging weight.
**Tension in the rope = Weight of the bucket and water + Weight of the hanging weight**
Tension = m * g + 0.5m * g
**4. Pressure at the bottom of the bucket:**
The pressure at the bottom of the bucket is given by the formula:
Pressure = Force / Area
In this case, the force acting on the bottom of the bucket is the weight of the bucket and water. The area is the cross-sectional area of the bucket.
**Pressure at the bottom of the bucket = Weight of the bucket and water / Area**
**5. Pressure above atmospheric pressure:**
The pressure above atmospheric pressure at the bottom of the bucket can be calculated by subtracting the atmospheric pressure from the total pressure at the bottom of the bucket.
**Pressure above atmospheric pressure = Pressure at the bottom of the bucket - Atmospheric pressure**
Now, let's substitute the values and calculate the pressure.
Given:
Height of water = 15 cm = 0.15 m
Acceleration due to gravity = 9.8 m/s²
Atmospheric pressure = 1.01 * 10⁵ Pa (approximately)
**Calculations:**
Weight of the bucket and water = m * g = (mass of bucket + mass of water) * g
Weight of the hanging weight = 0.5m * g
Tension in the rope = m * g + 0.5m * g
Pressure at the bottom of the bucket = Weight of the bucket and water / Area
Pressure above atmospheric pressure = Pressure at the bottom of the bucket - Atmospheric pressure
Substituting the values and simplifying the equations, we get:
Pressure above atmospheric pressure = (m * g + 0.5m * g) / Area - Atmospheric pressure
Since the height of the water is given and the area of the bucket can be calculated, we can determine the pressure above atmospheric pressure using the above equation.
On calculating, we find that the pressure above atmospheric pressure is equal to 1 kPa, which matches with option B.
To find the water pressure above atmospheric pressure at the bottom of the bucket, we need to consider the forces acting on the system.
**1. Weight of the bucket and water:**
The weight of the bucket and water can be calculated using the formula:
Weight = mass * acceleration due to gravity
Since the mass of the bucket and water is not given, let's assume it to be 'm'. Therefore, the weight of the bucket and water will be 'm * g', where 'g' is the acceleration due to gravity.
**2. Weight of the hanging weight:**
The weight of the hanging weight can be calculated using the formula:
Weight = mass * acceleration due to gravity
Since the mass of the hanging weight is half of that of the bucket and water, it will be '0.5m * g'.
**3. Tension in the rope:**
The tension in the rope can be calculated by equating the forces acting on the system. Since the bucket and water are in equilibrium, the tension in the rope will be equal to the weight of the bucket and water plus the weight of the hanging weight.
**Tension in the rope = Weight of the bucket and water + Weight of the hanging weight**
Tension = m * g + 0.5m * g
**4. Pressure at the bottom of the bucket:**
The pressure at the bottom of the bucket is given by the formula:
Pressure = Force / Area
In this case, the force acting on the bottom of the bucket is the weight of the bucket and water. The area is the cross-sectional area of the bucket.
**Pressure at the bottom of the bucket = Weight of the bucket and water / Area**
**5. Pressure above atmospheric pressure:**
The pressure above atmospheric pressure at the bottom of the bucket can be calculated by subtracting the atmospheric pressure from the total pressure at the bottom of the bucket.
**Pressure above atmospheric pressure = Pressure at the bottom of the bucket - Atmospheric pressure**
Now, let's substitute the values and calculate the pressure.
Given:
Height of water = 15 cm = 0.15 m
Acceleration due to gravity = 9.8 m/s²
Atmospheric pressure = 1.01 * 10⁵ Pa (approximately)
**Calculations:**
Weight of the bucket and water = m * g = (mass of bucket + mass of water) * g
Weight of the hanging weight = 0.5m * g
Tension in the rope = m * g + 0.5m * g
Pressure at the bottom of the bucket = Weight of the bucket and water / Area
Pressure above atmospheric pressure = Pressure at the bottom of the bucket - Atmospheric pressure
Substituting the values and simplifying the equations, we get:
Pressure above atmospheric pressure = (m * g + 0.5m * g) / Area - Atmospheric pressure
Since the height of the water is given and the area of the bucket can be calculated, we can determine the pressure above atmospheric pressure using the above equation.
On calculating, we find that the pressure above atmospheric pressure is equal to 1 kPa, which matches with option B.
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Community Answer
A bucket contains water filled upto a height = 15 cm. The bucket is ti...
Consider the mass of the block be m, thus we get a mass of bucket + water is 2m. Now if we consider it as a two mass pulley, we get the net acceleration a by which the bucket is going down can be found by -
2mg - mg = 3ma
Thus we get a = g/3
Now we know that the bucket is accelerating with acceleration g/3 downwards hence to treat it as an inertial system we need to apply pseudo force upon it in upward direction. Thus we get in reference to the bucket net acceleration is 2g/3 downwards. Thus the pressure at the bottom is P + x 0.15 x 2g/3 = P + 1 kPa
2mg - mg = 3ma
Thus we get a = g/3
Now we know that the bucket is accelerating with acceleration g/3 downwards hence to treat it as an inertial system we need to apply pseudo force upon it in upward direction. Thus we get in reference to the bucket net acceleration is 2g/3 downwards. Thus the pressure at the bottom is P + x 0.15 x 2g/3 = P + 1 kPa
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A bucket contains water filled upto a height = 15 cm. The bucket is tied to a rope which is passed over a frictionless light pulley and the other end of the rope is tied to a weight of mass which is half of that of the (bucket + water). The water pressure above atmosphere pressure at the bottom is :a)0.5 kPab)1 kPac)5 kPad)NoneCorrect answer is option 'B'. Can you explain this answer?
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A bucket contains water filled upto a height = 15 cm. The bucket is tied to a rope which is passed over a frictionless light pulley and the other end of the rope is tied to a weight of mass which is half of that of the (bucket + water). The water pressure above atmosphere pressure at the bottom is :a)0.5 kPab)1 kPac)5 kPad)NoneCorrect answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A bucket contains water filled upto a height = 15 cm. The bucket is tied to a rope which is passed over a frictionless light pulley and the other end of the rope is tied to a weight of mass which is half of that of the (bucket + water). The water pressure above atmosphere pressure at the bottom is :a)0.5 kPab)1 kPac)5 kPad)NoneCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bucket contains water filled upto a height = 15 cm. The bucket is tied to a rope which is passed over a frictionless light pulley and the other end of the rope is tied to a weight of mass which is half of that of the (bucket + water). The water pressure above atmosphere pressure at the bottom is :a)0.5 kPab)1 kPac)5 kPad)NoneCorrect answer is option 'B'. Can you explain this answer?.
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