To calculate the distance covered by the body along the semicircular path, we need to find the circumference of the semicircle.

The formula for the circumference of a circle is given by:
C = 2πr, where C is the circumference and r is the radius.

Since we are dealing with a semicircle, the radius is half of the diameter. Let's assume the radius of the semicircle is 'r'.

The distance covered along the semicircular path can be calculated by using the formula for the arc length of a circle:
S = rθ, where S is the arc length, r is the radius, and θ is the central angle in radians.

In a semicircle, the central angle is π radians (180 degrees). Therefore, the distance covered will be:
S = rπ

Given that the distance covered is 5 meters, we can set up the equation:
5 = rπ

Solving for 'r', we get:
r = 5/π

Plugging this value back into the formula for the circumference, we find:
C = 2π(5/π) = 10 meters

Therefore, the distance covered along the semicircular path is 10 meters.



Displacement is a vector quantity that refers to the straight-line distance and direction from the initial position to the final position. In the case of a semicircular path, the displacement can be calculated as the straight-line distance between the starting point and the ending point of the semicircle.

Since the semicircular path is symmetrical, the starting and ending points are equidistant from the midpoint of the diameter. Let's assume the diameter of the semicircle is 'd'.

The displacement can be calculated using the Pythagorean theorem:
Displacement = √(d^2 - r^2)

In this case, since the radius is half of the diameter, we have:
Displacement = √(d^2 - (d/2)^2)

Simplifying further, we get:
Displacement = √(d^2 - d^2/4)
Displacement = √(3d^2/4)

Given that the distance covered is 5 meters, we can set up the equation:
5 = √(3d^2/4)

Squaring both sides of the equation, we have:
25 = 3d^2/4

Solving for 'd', we get:
d^2 = (25*4)/3
d^2 = 100/3

Taking the square root of both sides, we find:
d ≈ √(100/3)
d ≈ 5.77 meters

Therefore, the displacement along the semicircular path is approximately 5.77 meters.



To find the ratio of the distance covered to the displacement, we divide the distance covered by the displacement:
Ratio = Distance Covered / Displacement

Ratio = 10 meters / 5.77 meters

Ratio ≈ 1.73

Therefore, the ratio of the distance covered to the displacement is approximately 1.73.