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An ac circuit, the current is given by i = 4 sin (100pt + 30º) ampere. The current becomes maximum first time (after t = 0) at t equal to
  • a)
    (1/200) sec
  • b)
    (1/300) sec
  • c)
    (1/50) sec
  • d)
    None of the above
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
An ac circuit, the current is given by i = 4 sin (100pt + 30º) am...
i=4sin(100πt+ π/6)
For I to be maximum
di/dt=0
therefore,4x100π(cos(100πt+π/6)=0
therefore, ωs(100πt+ π/6)=0
for the first time cosθ=0 at π/2
⇒ 100πt+ π/6= π/2
⇒ 100πt= π/3
⇒ πt= π/300
T=1/300
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An ac circuit, the current is given by i = 4 sin (100pt + 30º) am...
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