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Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force F is applied on 2m as shown in the figure. Now the same force F is applied from the right on m. In the two cases respectively, the ratio force of contact between the two block will be :


                     

  • a)
     Same 

  • b)
    1 : 2 

  • c)
     2 : 1

  • d)
    1 : 3

Correct answer is option 'B'. Can you explain this answer?
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Two blocks are in contact on a frictionless table. One has mass m and ...








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Two blocks are in contact on a frictionless table. One has mass m and ...
Let's generalize this question by considering two blocks "m" and "M", and the force "F" is acting on M. Two things to note is that the force of contact "N" always acts towards the body (or away from the other one) and both the blocks will have same acceleration as they are always joined together (they are separated below only for the sake of understanding).
So, the contact force is directly proportional to the mass of the block on which the force is not acting. 
- In the first case, N = (F x 2m)/3m = 2F/3 
- In the second case, N = (F x m)/3m = F/3
So, the ratio of contact forces is 2 : 1 (option C)
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Two blocks are in contact on a frictionless table. One has mass m and ...
  • If F is applied force then acceleration of the system is F/2m + m = F/3m
  • Now when we apply the force from the left, the force applied on the block m is F/3m = F/3. This will be the force in the contact.
  • When we apply the force from the right from on the block will be 2Fm/3 = 2F/3, this will be the force on the contact then.
So the ratio is F/3 : 2F/3 = 1 : 3
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Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force F is applied on 2m as shown in the figure. Now the same force F is applied from the right on m. In the two cases respectively, the ratio force of contact between the two block will be : a)Sameb)1 : 2c)2 : 1d)1 : 3Correct answer is option 'B'. Can you explain this answer?
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