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In a photoelectric effect experiment, ultraviolet light of wavelength 320 nm falls on the photocathode with work function of 2.1 eV. The stopping potential should be close to
- a)1.8 V
- b)1.6 V
- c)2.2 V
- d)2.4 V
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
In a photoelectric effect experiment, ultraviolet light of wavelength ...
We know :
eV =(hc/ lambda ) - work function
here , h =6.63× 10^(-34) ,c = 3×10^8, lambda =320×10^(-9) and work function= 2.1eV=2.1×1.6×10^(-19).
On substituting these values in above equation you get answer. option a.
eV =(hc/ lambda ) - work function
here , h =6.63× 10^(-34) ,c = 3×10^8, lambda =320×10^(-9) and work function= 2.1eV=2.1×1.6×10^(-19).
On substituting these values in above equation you get answer. option a.
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In a photoelectric effect experiment, ultraviolet light of wavelength ...
Photoelectric effect
The photoelectric effect is the phenomenon where electrons are emitted from a material when light of a certain frequency or higher (i.e., ultraviolet light or higher energy photons) is incident on it. This effect can be explained using the concept of photons and the energy required to free an electron from the material.
Work function
The work function of a material is the minimum amount of energy required to remove an electron from the material. It is typically given in electron volts (eV). In this case, the work function of the photocathode is given as 2.1 eV.
Stopping potential
The stopping potential is the potential difference required to stop the emitted electrons from reaching the anode. When the stopping potential is applied, the electrons lose all their kinetic energy and come to a stop.
Calculating the stopping potential
To calculate the stopping potential, we need to consider the energy of the incident photons and the work function of the photocathode.
The energy of a photon can be calculated using the equation: E = hc/λ, where E is the energy in joules, h is the Planck's constant (6.63 x 10^-34 J*s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of light in meters.
Converting the given wavelength of 320 nm to meters: λ = 320 nm = 320 x 10^-9 m.
Plugging the values into the equation: E = (6.63 x 10^-34 J*s * 3 x 10^8 m/s) / (320 x 10^-9 m) = 6.20 x 10^-19 J.
Next, we need to convert the energy from joules to electron volts (eV). 1 eV is equivalent to 1.6 x 10^-19 J.
Converting the energy to eV: E = (6.20 x 10^-19 J) / (1.6 x 10^-19 J/eV) = 3.88 eV.
Now, to calculate the stopping potential, we subtract the work function from the energy of the incident photons: Stopping potential = Energy - Work function = 3.88 eV - 2.1 eV = 1.78 eV.
Conclusion
The calculated stopping potential is 1.78 eV, which is closest to the given option 'A' of 1.8 V. Therefore, the correct answer is option 'A' - 1.8 V.
The photoelectric effect is the phenomenon where electrons are emitted from a material when light of a certain frequency or higher (i.e., ultraviolet light or higher energy photons) is incident on it. This effect can be explained using the concept of photons and the energy required to free an electron from the material.
Work function
The work function of a material is the minimum amount of energy required to remove an electron from the material. It is typically given in electron volts (eV). In this case, the work function of the photocathode is given as 2.1 eV.
Stopping potential
The stopping potential is the potential difference required to stop the emitted electrons from reaching the anode. When the stopping potential is applied, the electrons lose all their kinetic energy and come to a stop.
Calculating the stopping potential
To calculate the stopping potential, we need to consider the energy of the incident photons and the work function of the photocathode.
The energy of a photon can be calculated using the equation: E = hc/λ, where E is the energy in joules, h is the Planck's constant (6.63 x 10^-34 J*s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of light in meters.
Converting the given wavelength of 320 nm to meters: λ = 320 nm = 320 x 10^-9 m.
Plugging the values into the equation: E = (6.63 x 10^-34 J*s * 3 x 10^8 m/s) / (320 x 10^-9 m) = 6.20 x 10^-19 J.
Next, we need to convert the energy from joules to electron volts (eV). 1 eV is equivalent to 1.6 x 10^-19 J.
Converting the energy to eV: E = (6.20 x 10^-19 J) / (1.6 x 10^-19 J/eV) = 3.88 eV.
Now, to calculate the stopping potential, we subtract the work function from the energy of the incident photons: Stopping potential = Energy - Work function = 3.88 eV - 2.1 eV = 1.78 eV.
Conclusion
The calculated stopping potential is 1.78 eV, which is closest to the given option 'A' of 1.8 V. Therefore, the correct answer is option 'A' - 1.8 V.
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In a photoelectric effect experiment, ultraviolet light of wavelength 320 nm falls on the photocathode with work function of 2.1 eV. The stopping potential should be close toa)1.8 Vb)1.6 Vc)2.2 Vd)2.4 VCorrect answer is option 'A'. Can you explain this answer?
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In a photoelectric effect experiment, ultraviolet light of wavelength 320 nm falls on the photocathode with work function of 2.1 eV. The stopping potential should be close toa)1.8 Vb)1.6 Vc)2.2 Vd)2.4 VCorrect answer is option 'A'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about In a photoelectric effect experiment, ultraviolet light of wavelength 320 nm falls on the photocathode with work function of 2.1 eV. The stopping potential should be close toa)1.8 Vb)1.6 Vc)2.2 Vd)2.4 VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a photoelectric effect experiment, ultraviolet light of wavelength 320 nm falls on the photocathode with work function of 2.1 eV. The stopping potential should be close toa)1.8 Vb)1.6 Vc)2.2 Vd)2.4 VCorrect answer is option 'A'. Can you explain this answer?.
In a photoelectric effect experiment, ultraviolet light of wavelength 320 nm falls on the photocathode with work function of 2.1 eV. The stopping potential should be close toa)1.8 Vb)1.6 Vc)2.2 Vd)2.4 VCorrect answer is option 'A'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about In a photoelectric effect experiment, ultraviolet light of wavelength 320 nm falls on the photocathode with work function of 2.1 eV. The stopping potential should be close toa)1.8 Vb)1.6 Vc)2.2 Vd)2.4 VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a photoelectric effect experiment, ultraviolet light of wavelength 320 nm falls on the photocathode with work function of 2.1 eV. The stopping potential should be close toa)1.8 Vb)1.6 Vc)2.2 Vd)2.4 VCorrect answer is option 'A'. Can you explain this answer?.
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